我想使用JMF 2.1.1e以RTP格式捕获和流式传输音频。我写了一个简单的发射器,我可以发送和接收音频。但是当我在Wireshark中看到时,我将这些数据包看作是UDP。任何人都可以指出我的问题,请。为什么在使用jmf流时,它是UDP,而不是Wireshark中的RTP?
这里是我的功能负责音频捕获和传输。
public void captureAudio(){
// Get the device list for ULAW
Vector devices = captureDevices();
CaptureDeviceInfo captureDeviceInfo = null;
if (devices.size() > 0) {
//get the first device from the list and cast it as CaptureDeviceInfo
captureDeviceInfo = (CaptureDeviceInfo) devices.firstElement();
}
else {
// exit if we could not find the relevant capturedevice.
System.out.println("No such device found");
System.exit(-1);
}
Processor processor = null;
try {
//Create a Processor for the specified media.
processor = Manager.createProcessor(captureDeviceInfo.getLocator());
} catch (IOException ex) {
System.err.println(ex);
} catch (NoProcessorException ex) {
System.err.println(ex);
}
//Prepares the Processor to be programmed.
//puts the Processor into the Configuring state.
processor.configure();
//Wait till the Processor configured.
while (processor.getState() != Processor.Configured){
try {
Thread.sleep(100);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
//Sets the output content-type for this Processor
processor.setContentDescriptor(CONTENT_DESCRIPTOR);
/**
ContentDescriptor CONTENT_DESCRIPTOR
= new ContentDescriptor(ContentDescriptor.RAW_RTP);
*/
//Gets a TrackControl for each track in the media stream.
TrackControl track[] = processor.getTrackControls();
boolean encodingOk = false;
//searching through tracks to get a supported audio format track.
for (int i = 0; i < track.length; i++) {
if (!encodingOk && track[i] instanceof FormatControl) {
if (((FormatControl)
track[i]).setFormat(new AudioFormat(AudioFormat.ULAW_RTP, 8000, 8, 1)) == null)
{
track[i].setEnabled(false);
}
else {
encodingOk = true;
track[i].setEnabled(encodingOk);
System.out.println("enc: " + i);
}
} else {
// we could not set this track to ULAW, so disable it
track[i].setEnabled(false);
}
}
//If we could set this track to ULAW we proceed
if (encodingOk){
processor.realize();
while (processor.getState() != Processor.Realized){
try {
Thread.sleep(100);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
DataSource dataSource = null;
try {
dataSource = processor.getDataOutput();
} catch (NotRealizedError e) {
e.printStackTrace();
}
try {
String url= "rtp://192.168.1.99:49150/audio/1";
MediaLocator m = new MediaLocator(url);
DataSink d = Manager.createDataSink(dataSource, m);
d.open();
d.start();
System.out.println("transmitting...");
processor.start();
} catch (Exception e) {
e.printStackTrace();
}
}
}
请问,如果你发现任何不正确或模糊的东西。 在此先感谢。 :)
澄清:我有C#代码RTP流式传输peice的。当我捕捉使用Wireshark的的数据,我可以看到他们为RTP,但问题是,当我从JMF Wireshark的捕获数据流显示它们为UDP。而我的问题是,为什么?
我知道UDP和RTP的区别。
我认为问题出在CONTENT_DESCRIPTOR上,它是raw-rtp。 – shibli049 2012-04-05 04:40:40
我知道你的代码正在运行,除了你现在面临的问题。我们需要在JMF源代码中看到JMF在使用CONTENT_DESCRIPTOR时如何实现Processor类,就像Osbcure所说的那样。也许这是C#代码和Java JMF代码之间的区别。小心告诉你用于C#版本的流媒体库是什么? – ecle 2012-04-11 04:42:12
@eee:C#项目使用pjsipDll,我刚刚从朋友那里拿来测试wireshark中的数据包,而我不习惯使用C#。所以,不能给你任何关于C#的更多细节。 – shibli049 2012-04-11 06:56:58