精灵运动的MultiTouch控件 - cocos2d

Question

我一直在处理这个问题很长一段时间。 我想要做的是通过在屏幕左侧或右侧触摸来控制CCSprite的右/左移动。

如果在每次触摸后抬起手指，这样做不成问题。但我想要的最好用一个例子来描述： 玩家触摸屏幕的左侧，精灵向左移动。现在玩家（虽然还在触摸左侧）触及右侧......精灵现在应该向右移动。现在玩家的左手边和右手边都有一个手指，如果他现在从右侧抬起手指，精灵应该再次向左移动。

这是我现在有：

-(void)ccTouchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { 
    NSSet *allTouches = [event allTouches]; 
    UITouch * touch = [[allTouches allObjects] objectAtIndex:0]; 
    CGPoint location = [touch locationInView: [touch view]]; 
    location = [[CCDirector sharedDirector] convertToGL:location]; 

    if (location.x < 240) { 
     [player walk:kkMoveLeft]; 
    } else if (location.x > 240) { 
     [player walk:kkMoveRight]; 
    } 

    //Swipe Detection Part 1 
    firstTouch = location; 
} 

-(void) ccTouchesEnded:(NSSet *)touches withEvent:(UIEvent *)event { 
    NSSet *allTouches = [event allTouches]; 
    UITouch * touch = [[allTouches allObjects] objectAtIndex:0]; 
    CGPoint location = [touch locationInView: [touch view]]; 
    location = [[CCDirector sharedDirector] convertToGL:location]; 

    //Swipe Detection Part 2 
    lastTouch = location; 

    float swipeLength = ccpDistance(firstTouch, lastTouch); 

    if (firstTouch.y < lastTouch.y && swipeLength > 60) { 
     [player jump:kkJumpUp]; 
    } else if (firstTouch.y > lastTouch.y && swipeLength > 60){ 
     [player jump:kkJumpDown]; 
    } 

    [player endWalk]; 

} 

我会很感激，如果有人可以告诉我如何去了解这一点。谢谢 。

更新我的解决方案：

//1. Enable multitouch in the appDelegate 
[glView setMultipleTouchEnabled:YES]; 

//2. Create an Array to keep track of active touches 
touchArray = [[NSMutableArray alloc] init]; 

//3. Touch Methods 
-(void)ccTouchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { 

    for (UITouch *touch in touches) { 
     if (![touchArray containsObject:touch]) { 
      [touchArray addObject:touch]; 
      CGPoint location = [touch locationInView:[touch view]]; 
      location = [[CCDirector sharedDirector] convertToGL:location]; 
      CCLOG(@"start: %f", location.x); 
      if (location.x < 240) { 
       [player walk:kkMoveLeft]; 
      } else if (location.x > 240) { 
       [player walk:kkMoveRight]; 
      } 
     } 
    } 

} 

-(void) ccTouchesEnded:(NSSet *)touches withEvent:(UIEvent *)event { 

    for (UITouch *touch in touches) { 
     [touchArray removeObject:touch]; 
     CGPoint location = [touch locationInView:[touch view]]; 
     location = [[CCDirector sharedDirector] convertToGL:location]; 
     CCLOG(@"end: %f", location.x); 
    } 

    for (UITouch *touch in touchArray) { 
     CGPoint location = [touch locationInView:[touch view]]; 
     location = [[CCDirector sharedDirector] convertToGL:location]; 
     CCLOG(@"still: %f", location.x); 
     if (location.x < 240) { 
      [player walk:kkMoveLeft]; 
     } else if (location.x > 240) { 
      [player walk:kkMoveRight]; 
     } 
    } 


    if ([touchArray count] == 0) { 
     [player endWalk]; 
    } 

} 

Answer 1

如果我理解正确的话你的问题，你应该做的是：

1. 在ccTouchesEnded

   ，而不是简单地调用endWalk，查看任何触摸仍然存在（这样做，你可以遍历allTouches）;

2. 在适当的情况下（即，触摸仍在激活玩家），请致电startWalk。

3. 如果没有触摸，请拨打endWalk。

的代码将类似于你有什么ccTouchesBegan，只有你遍历（我不知道什么allTouches包含索引0 touchesEnded）。

OLD答：

你不是说你是如何现在处理任何接触。在任何情况下，要走的路是定义ccTouches*方法（与ccTouch*），其中*可以是：Began，Moved,Ended。

-(void)tccTouchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { 
UITouch *touch = [[event allTouches] anyObject]; 
CGPoint location = [touch locationInView:[touch view]]; 
location = [[CCDirector sharedDirector] convertToGL:location]; 
    ... 
} 
-(void)ccTouchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { 
    ... 
} 
-(void)ccTouchesEnded:(NSSet *)touches withEvent:(UIEvent *)event { 
    ... 
} 

记住的touchesBegan在检测到的每个新触摸解雇。因此，如果您想知道当前所有触摸的状态，则必须使用allTouches。

也看看this post from iphonesdk，我发现这些方法中触摸的语义有洞察力。