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我正试图在我的baysis2 FGPA上使用verilog创建一个简单的4位密码系统。我想使用7段显示器显示输入的数字(它们将使用键盘输入)。现在我只是测试以确保输入正确的数字。问题是,七段显示器的第一个数字在所有其他显示器都没有亮时不亮。我已经在多个电路板上尝试过,并且所有其他数字都是由相同的电线启用的,都很好。这是为什么发生?Baysis2 Verilog - 7段显示的第一位不能工作
module enter_password(
input wire clk, reset,
input wire ps2d, ps2c, rx_en,
output wire [6:0] seven_seg_display,
output wire assert_seg);
wire [7:0] scan_out;
wire [7:0] ascii_code;
//initial seven_seg_display = 7'b0000000;
assign assert_seg = 1'b1;
// instantiate ps2 receiver
ps2_rx ps2_rx_unit(
.clk(clk), .reset(reset), .rx_en(1'b1),
.ps2d(ps2d), .ps2c(ps2c),
.rx_done_tick(scan_done_tick), .dout(scan_out));
// instantiate key-to-ascii code conversion circuit
Scan_to_ascii key2ascii(.key_code(scan_out), .ascii_code(ascii_code));
assign seven_seg_display =
ascii_code == 8'h30 ? 7'b0000001: //0
ascii_code == 8'h31 ? 7'b1001111: //1
ascii_code == 8'h32 ? 7'b0010010: //2
ascii_code == 8'h33 ? 7'b0000110: //3
ascii_code == 8'h34 ? 7'b1001100: //4
ascii_code == 8'h35 ? 7'b0100100: //5
ascii_code == 8'h36 ? 7'b0100000: //6
ascii_code == 8'h37 ? 7'b0001111: //7
ascii_code == 8'h38 ? 7'b0000000: //8
ascii_code == 8'h39 ? 7'b0000100: //9
7'b1111111; //e for error 0
endmodule
UCF
NET "seven_seg_display[6]" LOC = "L14"; # Bank = 1, Signal name = CA
NET "seven_seg_display[5]" LOC = "H12"; # Bank = 1, Signal name = CB
NET "seven_seg_display[4]" LOC = "N14"; # Bank = 1, Signal name = CC
NET "seven_seg_display[3]" LOC = "N11"; # Bank = 2, Signal name = CD
NET "seven_seg_display[2]" LOC = "P12"; # Bank = 2, Signal name = CE
NET "seven_seg_display[1]" LOC = "L13"; # Bank = 1, Signal name = CF
NET "seven_seg_display[0]" LOC = "M12"; # Bank = 1, Signal name = CG
#NET "dp" LOC = "N13"; # Bank = 1, Signal name = DP
NET "assert_seg" LOC = "K14"; # Bank = 1, Signal name = AN3
NET "assert_seg" LOC = "M13"; # Bank = 1, Signal name = AN2
NET "assert_seg" LOC = "J12"; # Bank = 1, Signal name = AN1
NET "assert_seg" LOC = "F12"; # Bank = 1, Signal name = AN0
为什么'assert_seg'分配给4个引脚?该代码不应该通过“翻译”步骤。您的代码没有7段显示器的时间复用器,需要驱动所有4位数字。请参阅电路板的原理图以进行说明。 – Paebbels
电路板的原理图在哪里? – e19293001
您是否尝试断言最低位?也就是说,'wire assert_seg [3:0]'''assert_seg = 4'b0001' - 'NET'assert_seg [0]“LOC =”K14“'。该电路被设计为在任何时间只运行7段显示器中的一个(其更新频率高于人眼可以感知的)。也许它不能在所有显示器上持续显示一个值。 [来源](http://www.digilentinc.com/Data/Products/BASYS2/Basys2_rm.pdf) – Hida