0
我有我这样创建了一个功能:如何更改此函数中返回值的格式?
create or replace function core.nrt_summary_by_param_id(int) returns table (reason_type_id int, reason_id int, descr varchar(256), num int, pct numeric, cause_rank int) as $$
begin
return query
with r3 as (
//A bunch of queries
)
select
r3.reason_type_id,
r3.reason_id,
r3.desc,
r3.num,
r3.pct,
r3.cause_rank
from r3;
where
r3.param_id = $1
return;
end
$$ language plpgsql;
当我调用该函数像这样:
select nrt_summary_by_param_id(5);
的结果是这样的:
nrt_summary_by_param_id
(1,2001,“A”,14,19.72,1)
(1,2006, “B”,9,12.68,2)
(1,2202, “C”,8,11.27,3)
(1,2002, “d” ,8,11.27,3)
(1,2302, “E”,7,9.86,5)
(1,2201, “F”,4,5.63,6)
( 1,2206,“G”,4,5.63,6)
(1,2301,“H”,2,2.82,8)
(1,2303, “I”,2,2.82,8)
(1,2005, “J”,2,2.82,8)
(1,2004, “K” ,2,2.82,8)
(1,2204, “L”,2,2.82,8)
(,, “M”,7,9.87,11)
(13行)
我如何从具有多个列的表中返回我的函数?我如何让每个单独的列显示出来?我希望返回结果是,如果函数内部的整个查询通过命令行正常执行。谢谢!
@DiZou:如果你没有得到微妙的暗示:开始'SELECT * FROM nrt_summary_by_param_id(5);' – 2013-03-21 15:59:30
啊好了,这工作的感谢! – 2013-03-21 16:00:34