清除最后绘制的图形？ （撤消/重绘图）

Question

public function drag(e:MouseEvent) 
    { 
     lineDraw(mouseX, mouseY); 
     e.updateAfterEvent(); 

    } 
    public function lineDraw(X:int, Y:int):void 
    { 
     currentX = X; 
     currentY = Y; 

     graphics.lineStyle(size, color) 
     graphics.moveTo(previousX, previousY) 
     graphics.lineTo(currentX, currentY) 

     previousX = currentX; 
     previousY = currentY; 
    } 

非常简单的代码，我让我用我的鼠标画线。在MOUSE_DOWN之后MOUSE_MOVE上触发功能拖动。

我的问题是：我将如何去清除绘制的最后一行？基本上，一个ctrl+z/undo函数可以重复多次，我想要的。

我是否必须完全重写我的代码，并将每一行绘制到一个数组中，然后通过数组反向工作，删除行，因为我单击“撤消”？还是有另一个更好，更简单的解决方案呢？

谢谢！ :)

Answer 1

下面是一个例子：请参阅解释

private var undoStates:Vector.<Shape> = new Vector.<Shape>(); //holds all your undo states (HAS TO BE SHAPE SINCE AS3 DOESN"T LET YOU ISNTANTIATE A GRAPHICS OBJECT DIRECTLY) 
private var redoStates:Vector.<Shape> = new Vector.<Shape>(); //holds all your redo states 
private var undoLevels:int = 1; //how many undo levels you'd like to have 
private var redoLevels:int = 1; 

public function undo() { 
    if (undoStates.length > 0) { //make sure there is an undo state before preceeding 
     //add redo state 
     redoStates.push(getState()); 

     //if redo states are more than redoLevels, remove the oldest one 
     if (redoStates.length > redoLevels) redoStates.splice(0, 1); 

     //make the the last undo state the current graphics 
     graphics.clear(); //not sure if this line is required, can't recall if copyFrom clears first 
     graphics.copyFrom(undoStates.pop().graphics); //pop removes the last item from the array and returns it 
    } 
} 

public function redo() { 
    if (redoStates.length > 0) { 
     //add undo state 
     addUndo(); 

     //make the the last undo state the current graphics 
     graphics.clear(); //not sure if copy from (the next line) clears or not 
     graphics.copyFrom(redoStates.pop().graphics); 
    } 
} 

private function getState():Shape{ 
    var state:Shape = new Shape(); 
    state.graphics.copyFrom(graphics); //copy the current graphics into a new Graphics object 
    return state; 
} 

private function addUndo():void { 
    undoStates.push(getState()); //add the current state to the undo array 

    //if more undo states than undoLevels, remove the oldest one 
    if (undoStates.length > undoLevels) undoStates.splice(0, 1); 
} 

public function lineDraw(X:int, Y:int):void { 
    currentX = X; 
    currentY = Y; 


    //create undo state before we draw more 
    addUndo(); 

    graphics.lineStyle(size, color) 
    graphics.moveTo(previousX, previousY) 
    graphics.lineTo(currentX, currentY) 


    previousX = currentX; 
    previousY = currentY; 
}