2014-08-28 68 views
1

好的。我编辑我的问题。这是我的脚本:将多行转换为列编辑

CREATE TABLE #Table (
    Data Date, 
    Max_Temp Real, 
    Min_Temp Real, 
    Sr_Temp Real, 
    Sr_Temp_work Real) 

    SET NOCOUNT ON 
    DECLARE @StartTime Time 
    DECLARE @EndTime Time 
    DECLARE @StartTime1 Time 
    DECLARE @EndTime1 Time 
    DECLARE @data_start Date 
    DECLARE @data_stop Date 
    DECLARE @Data Date 
    DECLARE @Data_stop_while Date 
    DECLARE @Max_Temp Real 
    DECLARE @Min_Temp Real 
    DECLARE @Sr_Temp Real 
    DECLARE @Sr_Temp_work Real 


    SET @data_start = '20140713' 
    SET @data_stop = '20140719' 
    SET @StartTime = '00:00:00.000' 
    SET @EndTime = '23:59:59.998' 
    SET @StartTime1 = '08:00:00.000' 
    SET @EndTime1 = '16:30:00.000' 
    Set NOCOUNT OFF 

    SELECT @Data = @data_start 

    SELECT @Data_stop_while = DATEADD(day,1,@data_stop) 

    WHILE (@Data_stop_while<>@Data) 
    BEGIN 

    SELECT @Max_Temp = MAX(Value), @Min_Temp = MIN(Value), @Sr_Temp = AVG(Value) FROM INSQL.Runtime.dbo.History WHERE TagName IN ('VariableName') 
    and wwRetrievalMode = 'Cyclic' 
    AND DateTime >= (@Data + cast(@StartTime as datetime)) 
    AND DateTime <= (@Data + cast(@EndTime as datetime)) 


    SELECT @Sr_Temp_work = AVG(Value) FROM INSQL.Runtime.dbo.History WHERE TagName IN ('VariableName') 
    and wwRetrievalMode = 'Cyclic' 
    AND DateTime >= (@Data + cast(@StartTime1 as datetime)) 
    AND DateTime <= (@Data + cast(@EndTime1 as datetime)) 


    INSERT INTO #Table(Data, Max_Temp, Min_Temp, Sr_Temp, Sr_Temp_work) VALUES (@Data, @Max_Temp, @Min_Temp, @Sr_Temp, @Sr_Temp_work) 

    SELECT @Data = DATEADD(day,1,@Data) 

    END 

    SELECT Data, Max_Temp, Min_Temp, Sr_Temp, Sr_Temp_work FROM #Table GO 

当我设置一个特定的时间间隔,我有这些表,现在我需要转换的表:

enter image description here

我用支点,UNPIVOT与任何链接论坛和我不能这样做...

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请把实际的代码,而不是脚本的形象.. – 2014-08-28 09:13:56

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还向我们展示了预期的输出... – 2014-08-28 09:16:08

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请张贴实际的代码 – Adi 2014-08-28 09:20:28

回答

1

其实你需要使用动态透视和逆透视在一起。检查以下查询。使用到位,最后选择查询的下面的代码在你的程序中

DECLARE @Columns NVARCHAR(MAX) 
DECLARE @MainQuery NVARCHAR(MAX) 
SELECT @Columns = ISNULL(@Columns + ',','') + QUOTENAME(CONVERT(VARCHAR(10),Data,20)) 
FROM (SELECT DISTINCT Data FROM #Table) C 
SET @MainQuery ='SELECT [Temperature],' + @Columns + ' 
FROM 
(
    SELECT Data,Max_Temp,Min_Temp,Sr_Temp,Sr_Temp_work 
    FROM #Table 
) as T 
UNPIVOT 
(
    Value FOR [Temperature] in (Max_Temp,Min_Temp,Sr_Temp,Sr_Temp_work) 
) AS U 
PIVOT 
(
    MAX(Value) FOR [Data] IN ('+ @Columns +') 
) as P 
' 

EXEC sp_executesql @MainQuery 
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非常感谢。我在我的过程中使用了下面的代码来代替最后一个选择查询,并且没有响应(没有错误,没有转换)。我不知道为什么。但我在我的脚本中使用代码(没有我的过程)是好的 - 首先是旧表,然后是转换表:[link](http://i62.tinypic.com/1yo281.png) – Mini 2014-08-28 14:22:47

1

这是迄今为止最优雅的解决方案,但与一些动态SQL,你应该能够复制的逻辑。

DECLARE @temp TABLE (
    Data DATE, 
    Max_temp FLOAT, 
    Min_Temp FLOAT, 
    Sr_Temp FLOAT, 
    Sr_Temp_work FLOAT 
) 

INSERT INTO @temp 
select 
* 
from (values 
    ('2014-07-13',25.8,25.6,25.701,25.668), 
    ('2014-07-14',26.8,26.6,26.701,26.668), 
    ('2014-07-15',27.8,27.6,27.701,27.668), 
    ('2014-07-16',28.8,28.6,28.701,28.668))T (Data,Max_temp,Min_Temp,Sr_Temp, Sr_Temp_work) 
SELECT 
     Data, 
     Max_temp, 
     Min_Temp, 
     Sr_Temp, 
     Sr_Temp_work 
FROM @temp 


SELECT 
    'Max_temp' Temperature, 
    MAX([2014-07-13])[2014-07-13], 
    MAX([2014-07-14])[2014-07-14], 
    MAX([2014-07-15])[2014-07-15], 
    MAX([2014-07-16])[2014-07-16] 
FROM 
(
    SELECT 
     Data, 
     Max_temp, 
     Min_Temp, 
     Sr_Temp, 
     Sr_Temp_work 
    FROM @temp 
) SRC 
PIVOT (
    MAX(Max_temp) 
    FOR Data IN ([2014-07-13],[2014-07-14],[2014-07-15],[2014-07-16]) 
) AS pvt 
UNION ALL 
SELECT 
    'Min_Temp' Temperature, 
    MAX([2014-07-13])[2014-07-13], 
    MAX([2014-07-14])[2014-07-14], 
    MAX([2014-07-15])[2014-07-15], 
    MAX([2014-07-16])[2014-07-16] 
FROM 
(
    SELECT 
     Data, 
     Max_temp, 
     Min_Temp, 
     Sr_Temp, 
     Sr_Temp_work 
    FROM @temp 
) SRC 
PIVOT (
    MAX(Min_Temp) 
    FOR Data IN ([2014-07-13],[2014-07-14],[2014-07-15],[2014-07-16]) 
) AS pvt 
UNION ALL 
SELECT 
    'Sr_Temp' Temperature, 
    MAX([2014-07-13])[2014-07-13], 
    MAX([2014-07-14])[2014-07-14], 
    MAX([2014-07-15])[2014-07-15], 
    MAX([2014-07-16])[2014-07-16] 
FROM 
(
    SELECT 
     Data, 
     Max_temp, 
     Min_Temp, 
     Sr_Temp, 
     Sr_Temp_work 
    FROM @temp 
) SRC 
PIVOT (
    MAX(Sr_Temp) 
    FOR Data IN ([2014-07-13],[2014-07-14],[2014-07-15],[2014-07-16]) 
) AS pvt 
UNION ALL 
SELECT 
    'Sr_Temp_work' Temperature, 
    MAX([2014-07-13])[2014-07-13], 
    MAX([2014-07-14])[2014-07-14], 
    MAX([2014-07-15])[2014-07-15], 
    MAX([2014-07-16])[2014-07-16] 
FROM 
(
    SELECT 
     Data, 
     Max_temp, 
     Min_Temp, 
     Sr_Temp, 
     Sr_Temp_work 
    FROM @temp 
) SRC 
PIVOT (
    MAX(Sr_Temp_work) 
    FOR Data IN ([2014-07-13],[2014-07-14],[2014-07-15],[2014-07-16]) 
) AS pvt 

不同的注意!

通过行不使用行..

DECLARE 
    @data_start Date = '2014-07-13', 
    @data_stop Date = '2014-07-19' 

SELECT 
    [DateTime] Data 
    MAX(Value) Max_temp, 
    MIX(Value) Min_temp, 
    AVG(Value) Sr_Temp 
    AVG(case when CONVERT(TIME(7),DateTime) between '08:00:00.000' and '16:30:00.000' then Value else NULL end) Sr_Temp_work 
FROM INSQL.Runtime.dbo.History 
WHERE 
    TagName IN ('VariableName') and 
    wwRetrievalMode = 'Cyclic' AND 
    CONVERT(DATE, Datetime) between @data_start and @data_stop 
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谢谢你的回答,但不是重点..特别是我把代码。在Microsoft Report Services中,我选择了时间间隔。它不一定只有4天。 atdata_start和atdata_stop-我更改此值 – Mini 2014-08-28 10:05:25

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如果目标是用于报告服务,那么起始查询就足够了,只需使用Matrix并向列组添加日期并从那里开始工作。 – mxix 2014-08-28 10:09:48

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atdata_start和atdata_stop-我更改此值并值25.8,25.6,25.701,25.668等是从数据库中的VariableName中选择的 – Mini 2014-08-28 10:12:57