2009-02-24 61 views
8

我在我的应用程序中看到,我的解析XML文件中的xinclude在我的Java XSLT转换中不起作用。默认支持Java 6中的xinclude?

不过,虽然我做的:

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); 
factory.setXIncludeAware(true); 

我不是专门设置变压器厂为System.getProperty("javax.xml.transform.TransformerFactory")回报“空”。

我的问题:默认的Java(1.6或6)支持xinclude还是必须添加替代的XSLT解析器,如Apache Xerces?

回答

13

根据the spec,从Java 1.5(5)开始支持。我相信XInclude支持依靠namespace awareness,由于向后兼容性的原因,默认关闭。

public class XIncludeDemo { 

    private static final String XML = "<?xml version=\"1.0\"?>\n" 
      + "<data xmlns=\"foo\" xmlns:xi=\"http://www.w3.org/2001/XInclude\">\n" 
      + "<xi:include href=\"include.txt\" parse=\"text\"/>\n" 
      + "</data>\n"; 

    private static final String INCLUDE = "Hello, World!"; 

    public static void main(String[] args) throws Exception { 
     // data 
     final InputStream xmlStream = new ByteArrayInputStream(XML 
       .getBytes("UTF-8")); 
     final InputStream includeStream = new ByteArrayInputStream(INCLUDE 
       .getBytes("UTF-8")); 
     // document parser 
     DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); 
     factory.setXIncludeAware(true); 
     factory.setNamespaceAware(true); 
     DocumentBuilder docBuilder = factory.newDocumentBuilder(); 
     if (!docBuilder.isXIncludeAware()) { 
      throw new IllegalStateException(); 
     } 
     docBuilder.setEntityResolver(new EntityResolver() { 
      @Override 
      public InputSource resolveEntity(String publicId, String systemId) 
        throws SAXException, IOException { 
       if (systemId.endsWith("include.txt")) { 
        return new InputSource(includeStream); 
       } 
       return null; 
      } 
     }); 
     Document doc = docBuilder.parse(xmlStream); 
     // print result 
     Source source = new DOMSource(doc); 
     Result result = new StreamResult(System.out); 
     TransformerFactory transformerFactory = TransformerFactory 
       .newInstance(); 
     Transformer transformer = transformerFactory.newTransformer(); 
     transformer.transform(source, result); 
    } 

} 
+0

谢谢您的信息。我需要一些时间来应用它,看看我能否接受它。你给我的信息是我需要的。 – Roalt 2009-02-25 21:54:37