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我正在尝试使用游标移动来创建一个包含与其之前的字段相同的所有部分的列。在示例Sql - 关于游标和变量的问题
| column1 | column 2 |
| 1 | a |
| 2 | b |
| 3 | c |
would to go...
| column1 | column2 | column3 |
| 1 | a | b |
| 2 | b | c |
| 3 | c | NULL |
所以为了做到这一点我使用光标和更新语句基于如下的最后一个fetch语句尝试:
DECLARE myCursor1 CURSOR READ_ONLY
FOR
SELECT lname AS 'lnamerecoff'
FROM testingThis
ORDER BY lname
OPEN myCursor1
DECLARE @previous char(15)
DECLARE @new char(15)
SET @previous = FETCH NEXT FROM myCursor1
IF NOT EXISTS(SELECT * FROM sys.columns WHERE name = 'lnamerecoff'
AND object_id = OBJECT_ID('testingThis'))
ALTER TABLE testingThis ADD lnamerecoff int
WHILE @@FETCH_STATUS = 0
BEGIN
SET @new = FETCH NEXT FROM myCursor1
UPDATE testingThis
SET lnamerecoff = @new
SET @previous = @new
END
这是抛出一个语法错误靠近我的fetch语句。谁能帮我这个?谢谢!
LEAD和LAG函数会做了这个如此简单:/ – 2010-10-11 17:41:38
这些都不是在SQL Server 2005提供,虽然,是吗? – user416516 2010-10-11 17:48:13