在2D图形窗格上缩放信号

我正在摸索着想出一种在2D图形窗格上缩放信号的方式。故事是：我将我的应用程序连接到微控制器，并在固定的时间间隔内读取数据值（电压点）。现在我想在我的图形窗格上绘制它。例如：在2D图形窗格上缩放信号

enter image description here

于是起来，你在时间0看图片，电压也为0，这推移和后6个数据点，我会清除窗格和重做整个东西。

问题是，我怎样才能把这个电压转换成像素值，考虑到我希望图形窗格的中间是我的信号0，就像正常的笛卡尔图。有人可以帮助我弄清楚这种情况下的缩放算法吗？

2012-06-03 Saeid Yazdani

看起来像简单的数学：只需将宽度/ 2添加到您传递到绘图函数的所有X坐标。假设有6个点，你可以做以下的数组：

var g = this.CreateGraphics(); 
var points = new Point[6]{new Point(0, 0), new Point(10, 10), new Point(30, 0), new Point(40,20), new Point(50, 0), new Point(60,30)}; 
for (int i = 0; i < points.Length-1; i++) 
{ 
    g.DrawLine(Pens.Black, points[i].X + Width/2, Height/2 - points[i].Y, points[i + 1].X + Width/2, Height/2 - points[i + 1].Y); 
}

或者，可以调用TranslateTransform函数将所有进一步移动通过X和Y轴绘制的一些量。例如：

var g = this.CreateGraphics(); 
var points = new Point[6]{new Point(0, 0), new Point(10, 10), new Point(30, 0), new Point(40,20), new Point(50, 0), new Point(60,30)}; 
g.TranslateTransform(Width/2, 0, System.Drawing.Drawing2D.MatrixOrder.Append); 
for (int i = 0; i < points.Length-1; i++) 
{ 
    g.DrawLine(Pens.Black, points[i].X, Height/2 - points[i].Y, points[i + 1].X, Height/2 - points[i + 1].Y); 
}

来源

2012-06-03 20:41:31 Blablablaster

也许这将是有用的（记住，规模和翻译功能改变阵列分）：

private void pictureBox1_Paint(object sender, PaintEventArgs e) 
{ 
    var points = new PointF[6] { new PointF(0, 0), new PointF(30, 3), new PointF(90, 0), new PointF(190, 3.1f), new PointF(270, -0.5f), new PointF(360, 3.5f) }; 

    float maxX = (from p in points select p).Max(t => t.X); 
    float maxY = (from p in points select p).Max(t => t.Y);    

    float xSizeToFit = pictureBox1.Width; 
    float ySizeToFit = pictureBox1.Height/2; 
    float scaleX = xSizeToFit/maxX; 
    float scaleY = ySizeToFit/maxY; 

    // scale to fit to given size 
    ScalePoints(points, scaleX, scaleY); 
    // translate to center 
    TranslatePoints(points, this.pictureBox1.Width/2 - 0.5f * xSizeToFit, this.pictureBox1.Height/2 + 0.5f * ySizeToFit); 

    DrawAxis(e.Graphics, this.pictureBox1.Size); 
    e.Graphics.DrawLines(Pens.Black, points);     
} 

private void TranslatePoints(PointF[] points, float transX, float transY) 
{ 
    for (int i = 0; i < points.Length; i++) 
    { 
     points[i].X += transX; 
     points[i].Y = transY - points[i].Y; 
    } 
} 

private void ScalePoints(PointF[] points, float scaleX, float scaleY) 
{ 
    for (int i = 0; i < points.Length; i++) 
    { 
     points[i].X *= scaleX; 
     points[i].Y *= scaleY; 
    } 
} 

public void DrawAxis(Graphics g, Size size) 
{ 
    //x 
    g.DrawLine(Pens.Black, 0, size.Height/2, size.Width, size.Height/2); 
    //y 
    g.DrawLine(Pens.Black, size.Width/2, size.Height, size.Width/2, 0);   
} 

private void pictureBox1_Resize(object sender, EventArgs e) 
{ 
    pictureBox1.Invalidate(); 
}

来源

2012-06-03 23:11:32 Archibald

在2D图形窗格上缩放信号

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