SQL拆分制表符分隔列

我在包含标题字段及其相关结果的数据库中有一个制表符分隔的列。我需要一个查询协助，这个查询会根据IP列在单独的行中返回这些数据。以下是数据的样本，也是期望的结果。SQL拆分制表符分隔列

下面的查询产生这个结果。

DECLARE @Tmp TABLE (ID int Identity(1,1), IP nvarchar(255),Results NVARCHAR(max)); 
INSERT into @Tmp select top 1 ip, Results from MyTable where results like 'Package%' 
select * from @Tmp

这是期望的结果。

IP    Package  Installed Version   Required Version 
10.48.8.28  nss   3.21.0-9.el7_2.x86_64  3.21.3-2.el7_3 
10.48.8.28  nss-sysinit 3.21.0-9.el7_2.x86_64  3.21.3-2.el7_3 
10.48.8.28  nss-tools 3.21.0-9.el7_2.x86_64  3.21.3-2.el7_3 
10.48.8.28  nss-util  3.21.0-2.2.el7_2.x86_64 3.21.3-1.1.el7_3

这是从SQL结果窗口复制到剪贴板的数据。

ID IP   Results 
1 10.46.8.28 Package Installed Version Required Version 
       python 2.7.5-39.el7_2.x86_64 2.7.5-48.el7 
       python-libs 2.7.5-39.el7_2.x86_64 2.7.5-48.el7

来源

2017-02-15 Eddie D

你可以发布你的样品数据作为消耗品吗？不可能告诉你在那里发生了什么。那两列？列分离在哪里？为什么只有第一行有ip？ –

@SeanLange我已经用照片更新了帖子，希望增加更多的清晰度。 –

创建示例数据

Declare @YourTable table (ID int,IP varchar(50),TabString varchar(max)) 
Insert Into @YourTable values 
(1,'444.333.222.11','Package Installed Version Required Version 
nss 3.21.0-9.el7_2.x86_64 3.21.3-2.el7_3 
nss-sysinit 3.21.0-9.el7_2.x86_64 3.21.3-2.el7_3 
nss-tools 3.21.0-9.el7_2.x86_64 3.21.3-2.el7_3 
nss-util 3.21.0-2.2.el7_2.x86_64 3.21.3-1.1.el7_3')

它看起来像这样

方案1（与解析功能）

Select A.ID 
     ,A.IP 
     ,Package    = Pos1 
     ,[Installed Version] = Pos2 
     ,[Required Version] = Pos3 
From @YourTable A 
Cross Apply [dbo].[udf-Str-Parse](A.TabString,char(13)) B 
Cross Apply [dbo].[udf-Str-Parse-Row](B.RetVal,char(9)) C 
Where B.RetVal is not null and B.RetSeq>1

选项2（不解析功能）

Select A.ID 
     ,A.IP 
     ,Package    = Pos1 
     ,[Installed Version] = Pos2 
     ,[Required Version] = Pos3 
From @YourTable A 
Cross Apply ( 
       Select RetSeq = Row_Number() over (Order By (Select null)) 
         ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)'))) 
       From (Select x = Cast('<x>' + replace((Select replace(A.TabString,char(13),'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as X 
       Cross Apply x.nodes('x') AS B(i) 
      ) B 
Cross Apply (
       Select Pos1 = ltrim(rtrim(xDim.value('/x[1]','varchar(max)'))) 
         ,Pos2 = ltrim(rtrim(xDim.value('/x[2]','varchar(max)'))) 
         ,Pos3 = ltrim(rtrim(xDim.value('/x[3]','varchar(max)'))) 
         ,Pos4 = ltrim(rtrim(xDim.value('/x[4]','varchar(max)'))) 
       From (Select Cast('<x>' + replace((Select replace(B.RetVal,char(9),'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml) as xDim) as X 
      ) C 
Where B.RetVal is not null and B.RetSeq>1

如果有兴趣

CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimiter varchar(10)) 
Returns Table 
As 
Return ( 
    Select RetSeq = Row_Number() over (Order By (Select null)) 
      ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)'))) 
    From (Select x = Cast('<x>' + replace((Select replace(@String,@Delimiter,'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as A 
    Cross Apply x.nodes('x') AS B(i) 
); 
--Thanks Shnugo for making this XML safe 
--Select * from [dbo].[udf-Str-Parse]('Dog,Cat,House,Car',',') 
--Select * from [dbo].[udf-Str-Parse]('John Cappelletti was here',' ') 
--Select * from [dbo].[udf-Str-Parse]('this,is,<test>,for,< & >',',')

CREATE FUNCTION [dbo].[udf-Str-Parse-Row] (@String varchar(max),@Delimiter varchar(10)) 
Returns Table 
As 
Return (
    Select Pos1 = ltrim(rtrim(xDim.value('/x[1]','varchar(max)'))) 
      ,Pos2 = ltrim(rtrim(xDim.value('/x[2]','varchar(max)'))) 
      ,Pos3 = ltrim(rtrim(xDim.value('/x[3]','varchar(max)'))) 
      ,Pos4 = ltrim(rtrim(xDim.value('/x[4]','varchar(max)'))) 
      ,Pos5 = ltrim(rtrim(xDim.value('/x[5]','varchar(max)'))) 
      ,Pos6 = ltrim(rtrim(xDim.value('/x[6]','varchar(max)'))) 
      ,Pos7 = ltrim(rtrim(xDim.value('/x[7]','varchar(max)'))) 
      ,Pos8 = ltrim(rtrim(xDim.value('/x[8]','varchar(max)'))) 
      ,Pos9 = ltrim(rtrim(xDim.value('/x[9]','varchar(max)'))) 
    From (Select Cast('<x>' + replace((Select replace(@String,@Delimiter,'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml) as xDim) as A 
) 
--Thanks Shnugo for making this XML safe 
--Select * from [dbo].[udf-Str-Parse-Row]('Dog,Cat,House,Car',',') 
--Select * from [dbo].[udf-Str-Parse-Row]('John <test> Cappelletti',' ') 
--Select * from [dbo].[udf-Str-Parse-Row]('A&B;C;D;E, F;<x>',';')

来源

2017-02-15 21:16:12

约翰谢谢你，这个解决方案让我进入了球场，但它基于数据库中的原始数据有点偏离。我附上了由DB产生的实际结果的图片。 –

@EddieD简易修复。给我一点时间。该图像是非常有帮助的 –

@EddieD查看更新的答案 –

如果你使用SQL Server 2016可以使用STRING_SPLIT()

据阿龙贝特朗这是最快的方式解析功能。看到这个https://sqlperformance.com/2016/03/sql-server-2016/string-split

Declare @YourTable table (ID int,IP varchar(50),TabString varchar(max)); 
Insert Into @YourTable values 
(1,'444.333.222.11','Package Installed Version Required Version 
nss 3.21.0-9.el7_2.x86_64 3.21.3-2.el7_3 
nss-sysinit 3.21.0-9.el7_2.x86_64 3.21.3-2.el7_3 
nss-tools 3.21.0-9.el7_2.x86_64 3.21.3-2.el7_3 
nss-util 3.21.0-2.2.el7_2.x86_64 3.21.3-1.1.el7_3'); 


;WITH CTE_Lines AS 
(
select ID, IP, a.ROWID , a.Lines from @YourTable 
    CROSS APPLY (
     SELECT 
      ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS ROWID, value Lines 
     FROM STRING_SPLIT(TabString, CHAR(13)) --Splits by new lines 
    ) a 
), CTE_Columns AS 
(
SELECT ID, IP, ROWID, b.ColsID, b.[Cols] FROM CTE_Lines 
    CROSS APPLY (
    SELECT 
     ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS ColsID, 
     value [Cols] 
     FROM STRING_SPLIT(Lines, CHAR(9)) --Splits by tabs 
    ) b 
    WHERE ROWID <> 1 --Removes the headers 
) 

SELECT ID, IP, [1] Package, [2] [Installed Version],[3] [Required Version] FROM 
(
    SELECT ID, IP, ROWID, ColsID, [Cols] FROM CTE_Columns 
) a 
PIVOT (MAX(a.Cols) FOR ColsId in ([1],[2],[3])) as pvt

来源

2017-02-17 11:40:05 Lobo

你的例子对我来说并不完美，但对我来说却是有用的指针。 – Peter

SQL拆分制表符分隔列

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