由两个分隔符将字符串拆分为两列

Question

我有一个字符串值，其数值由逗号分隔，然后由管道分隔。我想把它们分成两列的表格。我可以用一个分隔符分割字符串，但不幸的是无法找到一种方法来分割两个。请帮忙。

DECLARE @list NVARCHAR(MAX) = '1,101|2,202|3,303'; 

结果应该如下。

1 101 
2 202 
3 303 

在此先感谢。

Answer 1

如果您使用的是SQL Server 2016或Azure，则可以访问新的SPLIT_STRING函数。如果没有，我建议使用杰夫MODEN的DelimitedSplit8K功能，这被广泛认为是最快，最有效的SQL基于字符串可分流...

DECLARE @list NVARCHAR(MAX) = '1,101|2,202|3,303'; 

SELECT 
    Col1 = LEFT(dsk.Item, sl.SplitLocation - 1), 
    Col2 = SUBSTRING(dsk.Item, sl.SplitLocation + 1, LEN(dsk.Item)) 
FROM 
    dbo.DelimitedSplit8K(@list, '|') dsk -- code for DelimitedSplit8K can be found here... http://www.sqlservercentral.com/articles/Tally+Table/72993/ 
    CROSS APPLY (VALUES (ISNULL(NULLIF(CHARINDEX(',', dsk.Item, 1), 0), 1))) sl (SplitLocation); 

Answer 2

CREATE FUNCTION [dbo].[fn_Split_char](@text nvarchar(max), @delimiter varchar(20) = ' ') 
RETURNS @Strings TABLE 
( 
    position int IDENTITY PRIMARY KEY, 
    value nvarchar(max) 
) 
AS 
BEGIN 

DECLARE @index int 
SET @index = -1 

WHILE (LEN(@text) > 0) 
    BEGIN 
    SET @index = CHARINDEX(@delimiter , @text) 
    IF (@index = 0) AND (LEN(@text) > 0) 
     BEGIN 
     INSERT INTO @Strings VALUES (@text) 
      BREAK 
     END 
    IF (@index > 1) 
     BEGIN 
     INSERT INTO @Strings VALUES (LEFT(@text, @index - 1)) 
     SET @text = RIGHT(@text, (LEN(@text) - @index)) 
     END 
    ELSE 
     SET @text = RIGHT(@text, (LEN(@text) - @index)) 
    END 
    RETURN 
END 



Select LEFT(value, Charindex(',', value) - 1) , 
RIGHT(value, Charindex(',', Reverse(value)) - 1) , 
* from [fn_Split_char] ('1,101|2,202|3,303', '|') 

Answer 3

使用XML路径和跨应用到基于单个行创建多个行在管隔板，然后使用子串WRT逗号来导出两个期望列

Create table #temp(list nvarchar(max)) 
Insert into #temp values('1,101|2,202|3,303') 
SELECT 
    Substring(Tbl.Col.value('./text()[1]','varchar(50)'),1,1)as col1, 
    Substring(Tbl.Col.value('./text()[1]','varchar(50)'),charindex(',',Tbl.Col.value('./text()[1]','varchar(50)'),1)+1,len(Tbl.Col.value('./text()[1]','varchar(50)'))) 
FROM 
(Select cast('<a>'+ replace((SELECT list As [*] FOR XML PATH ('')), '|', '</a><a>') + '</a>' as xml)as t 
    from #temp) tl 
Cross apply 
tl.t.nodes('/a') AS Tbl(Col) 

Answer 4

尝试使用此表值函数，嵌入此SP到主SP

ALTER FUNCTION [dbo].[delimiter] 
(
@PARAM_IDS AS VARCHAR(MAX) 
@PARAM_DELIMITER AS CHAR(1) 
) 
RETURNS 
@NEW_TABLE TABLE 
(
NUM INT NOT NULL IDENTITY, 
ID INT NOT NULL 
) 
AS 
BEGIN 
DECLARE @NEXTSTRING AS NVARCHAR(MAX); 
DECLARE @POS AS INT; 
DECLARE @STRING AS NVARCHAR(MAX); 
DECLARE @DELIMITER AS NVARCHAR(MAX); 
SET @STRING = @PARAM_IDS; 
SET @DELIMITER = @PARAM_DELIMITER; 
SET @STRING = @STRING + @DELIMITER; 
SET @POS = CHARINDEX(@DELIMITER,@STRING); 

WHILE (@POS <> 0) 
BEGIN 
    SET @NEXTSTRING = SUBSTRING(@STRING,1,@POS - 1); 
    INSERT @NEW_TABLE (ID) VALUES (@NEXTSTRING); 
    SET @STRING = SUBSTRING(@STRING,@POS+1,len(@STRING)); 
    SET @POS = CHARINDEX(@DELIMITER,@STRING); 
END 
    RETURN 
END 

然后例如使用

SET @DETAILS_COUNT = (SELECT COUNT(*) FROM delimiter(@PARAM_MS_UNIT_ID, @DELIMITER));