拆分多个分隔符

Question

我有一个字符串，它包含由|像这样：

http://...|http://...|http://...

但某些URL里面我可以有caracheter |，所以我可以.split分割它（“| HTTP：//”），但问题是，某些URL里面包含了另一个网址，这样

http://...|http://..=http://...=http://...|http://...=http%25253A%25252F%25252F...

我那么，怎样才能使用正则表达式拆分通过|http:// or =http:// or =http%25253A%25252F%25252F ？

Answer 1

您可以使用下面的代码：

String str = "http://www.google.com|https://support.microsoft.com/en-us/kb/301982|http://www.tutorialspoint.com/java/lang/string_split.htm"; 
String delimiters = "\\|(?=http)"; 

// analyzing the string 
String[] urls = str.split(delimiters); 

// prints the number of tokens 
System.out.println("Count of urls= " + urls.length); 

for(String url: urls) { 
    System.out.println(url); 
} 

它会分裂的|其次http。此示例的输出是：

Count of urls = 3 
http://www.google.com 
https://support.microsoft.com/en-us/kb/301982 
http://www.tutorialspoint.com/java/lang/string_split.htm 

Answer 2

你可以试试下面的代码：

// As your question in this string contains three https 
String httpStr = "http://...|http://..=http://...=http://...|http://...=http%25253A%25252F%25252F..."; 
// Split the string with 'http' that preceded by | 
String[] https = httpStr.split("(?<=\\|)http"); 
for (String http : https) { 
    System.out.println("http = http" + http); 
} 

而且它的结果：

http = http://...| 
http = http://..=http://...=http://...| 
http = http://...=http%25253A%25252F%25252F...