在SQLITE中使用SUM函数

Question

我有这个基本的sqlite3数据库。在我的商店表中，我专注于numberOfItems类别。例如，在我的PurchaseToStore表中，4个不同的商店购买玉米饼，其数量（numberOfItems）为5,55,55,55。我想要做的是计算这些值的总和。所以，（55 + 55 + 55 + 5）= 170

CREATE TABLE Store(

storeName VARCHAR(30), 
storeid INTEGER, 
PRIMARY KEY(storeid) 

); 

CREATE TABLE item(

itemName VARCHAR(30) , 
itemId INTEGER, 
PRIMARY KEY(itemId) 

); 


CREATE TABLE PurchasedToStore(

storeid INTEGER, 
itemId INTEGER, 
numberOfItems INTEGER, 
expirationMonth Integer, 
PRIMARY KEY(storeid, itemID), 
FOREIGN KEY(storeid) REFERENCES STORE(storeid), 
FOREIGN KEY(itemid) REFERENCES item(itemid) 

); 


INSERT INTO Store Store('Meijer', 1); 
INSERT INTO Store VALUES('Kroger', 2); 
INSERT INTO Store VALUES('Walmart', 3); 
INSERT INTO Store VALUES('Kmart', 4); 


INSERT INTO item VALUES('taco', 556); 
INSERT INTO item VALUES('burrito', 557); 
INSERT INTO item VALUES('cheese', 600); 

INSERT INTO STORE VALUES(1, 556, 5, 12); 
INSERT INTO STORE VALUES(2, 556, 55, 11); 
INSERT INTO STORE VALUES(3, 556, 55, 10); 
INSERT INTO STORE VALUES(4, 556, 55, 2); 

这是我要尝试这样做：

SELECT sum(numberOfItems) 
FROM item join purchasetostore 
WHERE storeid = itemid; 

Answer 1

这是一个有点不清楚最终目标是什么，但一稍微改变你的条件会得到你想要的总和。您需要匹配两个表中的itemid;

SELECT sum(numberOfItems) 
FROM item join PurchasedToStore 
WHERE item.itemid = PurchasedToStore.itemid; 

可能稍微有用的查询可能包括项目的项目名称和每个名称的总和;

SELECT item.itemname, sum(numberOfItems) 
FROM item join PurchasedToStore 
WHERE item.itemid = PurchasedToStore.itemid 
GROUP BY item.itemname; 

A simple SQLfiddle with both queries。