<?
$tablae = mysql_query("SELECT * FROM order_history where (type!='rent_referral' AND type!='rental_balance') AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "' GROUP BY user_id");
while ($order = mysql_fetch_array($tablae)) {
?>
<tr>
<?
$tablaes = mysql_query("SELECT * FROM members where id='$order[user_id]'");
$user = mysql_fetch_array($tablaes);
$idsd=$user['id'];
$rPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE (type!='rent_referral' AND type!='rental_balance') AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "'");
$hdPaid = mysql_fetch_array($rPaid);
$sPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE user_id='$idsd' AND (type!='rent_referral' AND type!='rental_balance') AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "'");
while ($hPaid = mysql_fetch_array($sPaid)) {
?>
<td><?=$user['username']?></td>
<td><?=$hPaid['total']?></td>
<?
}
?>
</tr>
<? } ?>
这让我这个结果http://dl.dropbox.com/u/14384295/test.jpeg订购总计Sum函数使用
我要订购按降序价格总额。
我需要
$sPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE user_id='$idsd' AND (type!='rent_referral' AND type!='rental_balance') AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "'");
上总被降序排序。
将非日期传递给您的脚本会导致查询失败。如果你有错误,我可能会得到你的表的名字和更多的信息,我可以用它来直接攻击。 – DampeS8N 2010-12-22 15:26:49
日期在脚本中指定...这不是我已发布的整个页面。 – friendishan 2010-12-22 15:28:07