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我们正在试图分析我们的员工为了趋势和预测目的每小时工作多长时间。垂直计算列
我想通过计算垂直列中的所有值来计算人数。
这是每小时格式在SQL的输出
（我盘旋我要总结的值）
只要该值大于0，我想将其计为1，因为这是按小时计算的人数。
这是我的查询产生输出的一部分。
SELECT
--b.*,
b.EMPLOYEENAME,
B.DEPARTMENT,
CONVERT(datetime, LEFT(b.SHIFTA_start,17),103) AS SHIFTA_start,
CONVERT(datetime, LEFT(b.ShiftA_End,17),103) as ShiftA_End,
b.StartTime_HOUR,
b.StartTime_min,
b.EndTime_HOUR,
b.EndTime_min,
CASE WHEN b.[0H_START] < b.[0H_END] THEN b.[0H_START] ELSE b.[0H_END] END AS [0],
CASE WHEN b.[1H_START] < b.[1H_END] THEN b.[1H_START] ELSE b.[1H_END] END AS [1]
from
(
/*Step 2 - calculating minutes from starttime and endtime */
select a.*,
/**Calculating the number of minutes worked from start_time MIN **/
CASE WHEN a.StartTime_HOUR = 0 and a.[0] = 1 AND a.StartTime_min !=0 THEN cast(cast((60-a.StartTime_min) as decimal(10,2))/60 as decimal(10,2)) ELSE a.[0] END AS [0H_START],
CASE WHEN a.StartTime_HOUR = 1 and a.[1] = 1 AND a.StartTime_min !=0 THEN cast(cast((60-a.StartTime_min) as decimal(10,2))/60 as decimal(10,2)) ELSE a.[1] END AS [1H_START],
/**Calculating the number of minutes worked from END_time MIN **/
CASE WHEN a.EndTime_HOUR = 0 and a.[0] = 1 AND a.EndTime_min !=0 THEN cast(cast((a.EndTime_min) as decimal(10,2))/60 as decimal(10,2)) ELSE a.[0] END AS [0H_END],
CASE WHEN a.EndTime_HOUR = 1 and a.[1] = 1 AND a.EndTime_min !=0 THEN cast(cast((a.EndTime_min) as decimal(10,2))/60 as decimal(10,2)) ELSE a.[1] END AS [1H_END]
from
(--Step 1:
/*to determine 1 or 0 using the start and end hour
If time falls in the respective hour = 1
if time doesnt fall in the respective hours = 0*/
SELECT
[EMPLOYEENAME],
[DEPARTMENT],
[SHIFTA_start],
CASE WHEN [SHIFTA_START] !='' OR SHIFTA_START != NULL THEN CONVERT(datetime, LEFT([SHIFTA_START],17),103) ELSE NULL END AS SHIFTA_START_con,
CASE WHEN [SHIFTA_START] !='' OR SHIFTA_START != NULL THEN DATEPART(hh,CONVERT(datetime, LEFT([SHIFTA_START],17),103)) ELSE NULL END AS StartTime_HOUR,
CASE WHEN [SHIFTA_START] !='' OR SHIFTA_START != NULL THEN DATEPART(mi,CONVERT(datetime, LEFT([SHIFTA_START],17),103)) ELSE NULL END AS StartTime_min,
[SHIFTA_end],
CASE WHEN [SHIFTA_END] !='' OR SHIFTA_end != NULL THEN CONVERT(datetime, LEFT([SHIFTA_END],17),103) ELSE NULL END AS SHIFTA_END_con,
CASE WHEN [SHIFTA_END] !='' OR SHIFTA_end != NULL THEN DATEPART(hh,CONVERT(datetime, LEFT([SHIFTA_end],17),103)) ELSE NULL END AS EndTime_HOUR,
CASE WHEN [SHIFTA_END] !='' OR SHIFTA_end != NULL THEN DATEPART(mi,CONVERT(datetime, LEFT([SHIFTA_end],17),103)) ELSE NULL END AS EndTime_min,
CASE WHEN [SHIFTA_START] !='' AND 0 BETWEEN DATEPART(hh,CONVERT(datetime, LEFT([SHIFTA_START],17),103)) AND DATEPART (hh,CONVERT(datetime, LEFT([SHIFTA_end],17),103)) THEN 1 ELSE 0 END AS [0],
CASE WHEN [SHIFTA_START] !='' AND 1 BETWEEN DATEPART(hh,CONVERT(datetime, LEFT([SHIFTA_START],17),103)) AND DATEPART (hh,CONVERT(datetime, LEFT([SHIFTA_end],17),103)) THEN 1 ELSE 0 END AS [1]
from [DatabaseTable].[dbo].[ATTENDANCE]
where ShiftA_Start != '' and ShiftA_End !='' and shiftA_start != shiftA_End
)a
)b
请帮助，谢谢v多！
后的样本数据，文本，没有图像和提供查询你已经尝试了什么。 –
作为文本发布数据是什么意思？你的意思是用excel格式吗？ 我已经发布了查询，请看看。 @StanislovasKalašnikovas – Vannessa