MySQL的：分组结果

Question

我怎么能组我在查询结果像这样：

SELECT (
      SELECT SUM(wky) FROM table 
      WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16' 
      ) + 
      (SELECT SUM(earnings) FROM table 
      WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16')/.75 

上述查询返回WKY +（收入/ .75）在所有站点（每个站点都有一个WKY和收益我希望我的结果按site_id分组，因为上面的查询只返回所有人的收入总和。

谢谢！

Answer 1

SELECT site_id, (SUM(wky) + (SUM(earnings)/0.75)) 
FROM Earnings_Date 
WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16' 
GROUP BY site_id 

您的数据来自两个查询的同一张表，因此您可以合并它们。

Answer 2

SELECT (
     SELECT SUM(wky) FROM table 
     WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16' 
     ) + 
     (SELECT SUM(earnings) FROM table 
     WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16')/.75 

, site_id GROUP BY site_id 

:)