分组由分裂的结果列表

Question

，所以我有一些字符串列表中的

Folder1\File.png 
Folder1\File2.png 
File3.png 
File4.png 

，我想在一个split('\\')[0];例如组这些

foreach (var group in files.GroupBy(x => //mysplit)) 
{ 
    if (group.Count() > 1) 
    { 
     // this is a folder and its files are: group 
    } 
    else 
    { 
     //group is an individual file 
    } 
} 

，但我不知道如何通过这个拆分对文件进行分组？

Answer 1

所以我的解决办法是：

foreach (var groupedFiles in files.GroupBy(s => s.Split('\\')[0])) 
{ 
    if (Path.GetExtension(groupedFiles.Key) == string.Empty) 
    { 
      //this is a folder 
      var folder = groupedFiles.Key; 
      var folderFiles = groupedFiles.ToList(); 
    } 
    else 
    { 
      //this is a file 
      var file = groupedFiles.First(); 
    } 
} 

Answer 2

我愿意Contains()反斜杠只是项目组：

var lst1 = new string[] {"Folder1\\File.png", "Folder1\\File2.png" , "File3.png", "File4.png" }; 
var grps = lst1.GroupBy(x => x.Contains(@"\")); 
foreach (var g in grps) 
{ 
    if (g.Key) // we have a path with directory 
     Console.WriteLine(String.Join("\r\n", g.ToList())); 
    else // we have an individual file 
     Console.WriteLine(String.Join("\r\n", g.ToList())); 
}