复杂的分组查询

下面是我的sql查询，我已经把一些MAX（table_name），因为当使用group by时，我不能只放表名。如果我放了MAX，当有varchar值时需要一些时间来执行，请为varchar而不是MAX给出合适的聚合函数。复杂的分组查询

此外，那些MAX（table_name）都是相同的值，没有不同，我只需要打印它。

select distinct 
    t1.PartyName as Customer_Name, 
    SUM(t2.Amount) as Bill_Amount, 
    MAX(t2.VoucherNumber) as Invoice_Number, 
    SUM(i.Weight * t2.Aqty) as Weight, 
    CEILING(SUM(i.CBM * (t2.Aqty/c.Nos))) as CBM, 
    MAX(p.Channel) as Type, 
    MAX(p.RouteNo) as RouteNo, 
    MAX(t1.Adress3) as City 
from 
    Item i, 
    Party p, 
    Tran1 t1, 
    VTran2 t2, 
    Cases c 
Where 
    t1.VoucherNumber=t2.VoucherNumber and 
    t2.ItemName=i.Itemname and 
    p.PartyName=t1.PartyName and 
    t2.ItemName=c.ItemName and 
    p.RouteNo='" + routeNo1comboBox.Text + "' and 
    t1.LoadingStatus IS NULL and 
    t1.Date BETWEEN '" + startDate + "' and '" + endDate + "' 

GROUP BY t1.PartyName

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2014-12-03 Safa

您的'连接'条件可能是错误的。修复您的查询以使用propoer'join'语法，并且这可能会解决您的问题。 – 2014-12-03 12:32:34

如果'table_name'对于所有记录都是相同的，那么为什么你需要对它执行一个聚合函数，只需将它包含在'SELECT'列表中即可。 – 2014-12-03 12:35:12

嗨，戈登，感谢您的回复，您能否以我的加入示例为我提供小修改？之后，我可以轻松地赶上。 – Safa 2014-12-03 12:35:59

“另外，那些MAX（table_name）都是相同的值，没有不同，我只需要打印它。”

为什么你不能仅仅通过选择列表和组添加它们呢？

这一个不行？

select distinct 
    t1.PartyName as Customer_Name, 
    SUM(t2.Amount) as Bill_Amount, 
    t2.VoucherNumber as Invoice_Number, 
    SUM(i.Weight * t2.Aqty) as Weight, 
    CEILING(SUM(i.CBM * (t2.Aqty/c.Nos))) as CBM, 
    p.Channel as Type, 
    p.RouteNo as RouteNo, 
    t1.Adress3 as City 
from Item i, Party p, Tran1 t1, VTran2 t2, Cases c 
Where t1.VoucherNumber=t2.VoucherNumber 
and t2.ItemName=i.Itemname 
and p.PartyName=t1.PartyName 
and t2.ItemName=c.ItemName 
and p.RouteNo=''' + routeNo1comboBox.Text + ''' 
and t1.LoadingStatus IS NULL 
and t1.Date BETWEEN ''' + startDate + ''' and ''' + endDate + ''' 
GROUP BY t1.PartyName, cs,t2.VoucherNumber,p.Channel,p.RouteNo,t1.Adress3

来源

2014-12-03 12:39:22

非常感谢Alexandru Aliu为您提供简单易用的修改解决方案。 – Safa 2014-12-03 12:50:16

您不必添加distinct，因为你已经通过t1.PartyName，t2.VoucherNumber，p.Channel，p.RouteNo，t1.Adress3分组。

select 
    t1.PartyName as Customer_Name, 
    SUM(t2.Amount) as Bill_Amount, 
    t2.VoucherNumber as Invoice_Number, 
    SUM(i.Weight * t2.Aqty) as Weight, 
    CEILING(SUM(i.CBM * (t2.Aqty/c.Nos))) as CBM, 
    p.Channel as Type, 
    p.RouteNo as RouteNo, 
    t1.Adress3 as City 
from Item i, Party p, Tran1 t1, VTran2 t2, Cases c 
Where t1.VoucherNumber=t2.VoucherNumber 
and t2.ItemName=i.Itemname 
and p.PartyName=t1.PartyName 
and t2.ItemName=c.ItemName 
and p.RouteNo=''' + routeNo1comboBox.Text + ''' 
and t1.LoadingStatus IS NULL 
and t1.Date BETWEEN ''' + startDate + ''' and ''' + endDate + ''' 
GROUP BY t1.PartyName, cs,t2.VoucherNumber,p.Channel,p.RouteNo,t1.Adress3

来源

2014-12-03 12:58:03

复杂的分组查询

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