我有一个在dlib中定义的colume向量。我怎样才能将其转换为std :: vector?如何将dlib中的矩阵转换为std :: vector
typedef dlib::matrix<double,0,1> column_vector;
column_vector starting_point(4);
starting_point = 1,2,3,4;
std::vector x = ??
感谢
我有一个在dlib中定义的colume向量。我怎样才能将其转换为std :: vector?如何将dlib中的矩阵转换为std :: vector
typedef dlib::matrix<double,0,1> column_vector;
column_vector starting_point(4);
starting_point = 1,2,3,4;
std::vector x = ??
感谢
方法有很多种。你可以通过for循环来复制它。或者使用带迭代器的std :: vector构造函数:std::vector<double> x(starting_point.begin(), starting_point.end())
。
这将是你通常遍历矩阵的方式(不要紧,如果矩阵只有1列):
// loop over all the rows
for (unsigned int r = 0; r < starting_point.nr(); r += 1) {
// loop over all the columns
for (unsigned int c = 0; c < starting_point.nc(); c += 1) {
// do something here
}
}
那么,你为什么不遍历您的列向量和介绍每个值都变成新的std::vector
?这里是一个完整的例子:
#include <iostream>
#include <dlib/matrix.h>
typedef dlib::matrix<double,0,1> column_vector;
int main() {
column_vector starting_point(4);
starting_point = 1,2,3,4;
std::vector<double> x;
// loop over the column vector
for (unsigned int r = 0; r < starting_point.nr(); r += 1) {
x.push_back(starting_point(r,0));
}
for (std::vector<double>::iterator it = x.begin(); it != x.end(); it += 1) {
std::cout << *it << std::endl;
}
}
谢谢。但不应该是标准::矢量 x(starting_point.begin(),starting_point.end())? –
colddie
糟糕,没错。 –