如何创建月份名称作为sql中给定日期范围的列名称？

Question

我有如下数据：

表

---

country  date    value  
------------------------------------------------------ 
test1  5/1/2008   500 
test1  5/7/2008   200 
test1  5/8/2008   300 
test1  7/1/2008   100 
test1  7/2/2008   100 
test2  6/1/2008   100 

而且我想如下结果：

Result 
----------- 
countryName   May-08   Jun-08  July-08 
test1    1000    -   200 
test2     -    100 

Answer 1

这是从T-SQL Pivot? Possibility of creating table columns from row values

适应你可以看到它在这里工作：http://sqlfiddle.com/#!3/7b8c0/28

我想你可能需要反复折腾列排序

-- Static PIVOT 
SELECT * 
FROM (SELECT country, 
     CONVERT(char(3), date, 0) + '-' + 
     RIGHT(CONVERT(varchar, YEAR(date)), 2) AS date, 
     value 
FROM country) AS D 
PIVOT(SUM(value) FOR date IN([May-08],[Jun-08],[Jul-08])) AS P; 
GO 

-- Dynamic PIVOT 
DECLARE @T AS TABLE(y INT NOT NULL PRIMARY KEY); 

DECLARE 
@cols AS NVARCHAR(MAX), 
@y AS INT, 
@sql AS NVARCHAR(MAX) 

SELECT @cols = STUFF(
(SELECT N',' + QUOTENAME(y) AS [text()] 
FROM (SELECT DISTINCT CONVERT(char(3), date, 0) + '-' + 
     RIGHT(CONVERT(varchar, YEAR(date)), 2) AS y 
     FROM Country 
    ) AS Y 
ORDER BY y desc 
FOR XML PATH('')), 
1, 1, N'') 

-- Construct the full T-SQL statement 
-- and execute dynamically 
SET @sql = N'SELECT * 
FROM (SELECT country, CONVERT(char(3), date, 0) + ''-'' + 
     RIGHT(CONVERT(varchar, YEAR(date)), 2) AS date, value 
FROM Country) AS D 
PIVOT(SUM(value) FOR date IN(' + @cols + N')) AS P;' 

EXEC sp_executesql @sql 

Answer 2

你必须使用一个相当复杂的查询，使用LOOP它认为。

用于创建动态列名看看这个帖子：https://stackoverflow.com/a/10926106/1321564

与SQL Server你有一定的优势：https://stackoverflow.com/a/5638042/1321564