将日期时间拆分为日期/年/月/日名称和计数年份

Question

我通过使用触发器得到了从datetime中分割日期，月份年份，日期名称的问题，插入日期时间时，则在下一列中将拆分日期，时间，月份一年的姓名和数字年（知道我的数据中的男人有多大年纪）是可能的？

例如，如果我插入

INSERT INTO MAN VALUES ('04/06/1982') 

那么会是这样

DATETIME     DATE   MONTH  YEAR  DAYNAME  AGE 
04/06/1982 00:00:00  04   06  1982  friday  27 

Answer 1

试试这个： -

Declare @myDate datetime 
set @myDate='19820604' --YYYYMMDD 


Select @myDate as DateTime, 
     datename(day,@myDate) as Date, 
     month(@myDate) as Month, 
     datename(year,@myDate) as Year, 
     Datename(weekday,@myDate) as DayName, 
     DATEDIFF (year , @myDate , getdate()) as Age 

结果

╔══════════════════════════════╦══════╦═══════╦══════╦═════════╦══════════╗ 
    ║   DateTime   ║ DATE ║ MONTH ║ YEAR ║ DAYNAME ║ Age  ║ 
    ╠══════════════════════════════╬══════╬═══════╬══════╬═════════╬══════════╣ 
    ║ April, 06 1982 00:00:00+0000 ║ 4 ║  6 ║ 1982 ║ Friday ║  31 ║ 
    ╚══════════════════════════════╩══════╩═══════╩══════╩═════════╩══════════╝ 

SQL小提琴Demo

Answer 2

该代码已被轻微改变，以正确给予年龄。

Select myDate,myDateDate,myDateMonth,myDateYear,myDateDayName, Convert(varchar(50),Age)+ ' Years and '+Convert(varchar(50),nodays) +'days' {Age] from 
     (
     Select @myDate as myDate, 
       datename(day,@myDate) as myDateDate, 
       month(@myDate) as myDateMonth, 
       datename(year,@myDate) as myDateYear, 
       Datename(weekday,@myDate) as myDateDayName, 
       DATEDIFF (year , @myDate , getdate()) Age , 
       DATEDIFF  (dd , @myDate , getdate()) -365* DATEDIFF (year , @myDate , getdate()) as nodays 
     ) As a 

感谢 阿伦

Answer 3

这里有解决问题的两种方法：

-方法1：
你可以在你的表增加一些计算列，所以当您检索表格内容时，其他剩余的字段将在此时计算。

-- 1.1) Create the base of table 'MAN' 
CREATE TABLE [dbo].[MAN](
    [DATETIME] [datetime] NOT NULL 
) ON [PRIMARY] 
GO 

-- 1.2) Insert a record in it 
INSERT INTO MAN VALUES ('04/06/1982') 
GO 

-- 1.3) Add some computed columns 
ALTER TABLE MAN 
ADD 
    [DAY]  AS DATENAME(DAY, [DATETIME]), 
    [MONTH]  AS MONTH([DATETIME]), 
    [YEAR]  AS DATENAME(YEAR, [DATETIME]), 
    [DAYNAME] AS DATENAME(WEEKDAY, [DATETIME]), 
    [AGE]  AS DATEDIFF(YEAR, [DATETIME], GETDATE()) 
GO 

-- 1.4) See the result 
SELECT * FROM MAN 

-方法2：
当您创建表，您可以添加您需要的其余字段，以便在下一阶段添加插入/更新触发器来计算剩余字段并插入/更新它们。

-- 2.1) Create the table 'MAN' with all needed columns 
CREATE TABLE [dbo].[MAN](
    [DATETIME] [datetime]  NOT NULL, 
    [DAY]  [int]   NULL, 
    [MONTH]  [int]   NULL, 
    [YEAR]  [int]   NULL, 
    [DAYNAME] [nvarchar](10) NULL, 
    [AGE]  [int]   NULL 
) ON [PRIMARY] 
GO 

-- 2.2) Create Insert and update triggers in order to calculate the values of the rest fields while inserting/updating 
CREATE TRIGGER [dbo].[trCalculateRemainingDateFields] ON MAN 
AFTER INSERT, UPDATE 
AS 
BEGIN 
    SET NOCOUNT ON; 

    UPDATE MAN 
    SET 
     [DAY]  = DATENAME(DAY, MAN.[DATETIME]), 
     [MONTH]  = MONTH(MAN.[DATETIME]), 
     [YEAR]  = DATENAME(YEAR, MAN.[DATETIME]), 
     [DAYNAME] = DATENAME(WEEKDAY, MAN.[DATETIME]), 
     [AGE]  = DATEDIFF(YEAR, MAN.[DATETIME], GETDATE()) 

    FROM Inserted i 
    WHERE i.[DATETIME] = MAN.[DATETIME] 
END 
GO 


-- 2.3) Insert a record in it 
INSERT INTO MAN ([DATETIME]) VALUES ('04/06/1985') 
GO 

-- 2.4) See the result 
SELECT * FROM MAN 

-方法3：
创建其计算剩余字段可以是一个很好的选择主表的视图。

-- 3.1) Create the base of table 'MAN' 
CREATE TABLE [dbo].[MAN](
    [DATETIME] [datetime] NOT NULL 
) ON [PRIMARY] 
GO 

-- 3.2) Insert a record in it 
INSERT INTO MAN VALUES ('04/06/1982') 
GO 

-- 3.3) Create a view which is contained the remaining fields 
CREATE VIEW dbo.vMAN 
AS 
    SELECT [DATETIME], 
      DATENAME(DAY, [DATETIME])    AS [DAY], 
      MONTH([DATETIME])      AS [MONTH], 
      DATENAME(YEAR, [DATETIME])    AS [YEAR], 
      DATENAME(WEEKDAY, [DATETIME])   AS [DAYNAME], 
      DATEDIFF(YEAR, [DATETIME], GETDATE()) AS [AGE]  
    FROM MAN 
GO 

-- 3.4) See the result 
SELECT * FROM vMAN