按列排序但在结果中不包括该列

我一直在试图弄清楚如何修改此查询，以便结果集不包含numHits。我想以相同的顺序得到相同的结果，只是没有包含numHits。按列排序但在结果中不包括该列

SELECT 
    `newel_inventoryKeywordIdDictionaryId`.`inventoryId` 
    ,COUNT(`newel_inventoryKeywordIdDictionaryId`.`inventoryId`) as numHits 
FROM 
    `newel_inventoryKeywordIdDictionaryId` 
    , `newel_inventoryDictionary` 
WHERE 
    `newel_inventoryKeywordIdDictionaryId`.`dicId` = `newel_inventoryDictionary`.`dicId` 
    AND ( 
     `newel_inventoryDictionary`.`word` = 'alabaster' OR `newel_inventoryDictionary`.`word` = 'chess' 
    ) 
GROUP BY inventoryId 
ORDER BY numHits DESC;

样品的结果：

inventoryId, numHits 
6928, 2 
6929, 2 
6924, 2 
6925, 2 
13772, 2 
6926, 2 
18203, 1 
6931, 1 
13863, 1 
18402, 1

期望的结果：

inventoryId 
6928 
6929 
6924 
6925 
13772 
6926 
18203 
6931 
13863 
18402

来源

2015-06-14 kambythet

在你选中刚才设置'选择 newel_inventoryKeywordIdDictionaryId.inventoryId'没有'numHits' –

移动从SELECT子句该柱ORDER BY子句：

SELECT 
    `newel_inventoryKeywordIdDictionaryId`.`inventoryId` 
FROM 
    `newel_inventoryKeywordIdDictionaryId` 
    , `newel_inventoryDictionary` 
WHERE 
    `newel_inventoryKeywordIdDictionaryId`.`dicId` = `newel_inventoryDictionary`.`dicId` 
    AND ( 
     `newel_inventoryDictionary`.`word` = 'alabaster' OR `newel_inventoryDictionary`.`word` = 'chess' 
    ) 
GROUP BY inventoryId 
ORDER BY COUNT(`newel_inventoryKeywordIdDictionaryId`.`inventoryId`) DESC;

来源

2015-06-14 19:34:40

谢谢。完美的感觉！ – kambythet

SELECT 
`newel_inventoryKeywordIdDictionaryId`.`inventoryId` 
FROM 
`newel_inventoryKeywordIdDictionaryId` 
, `newel_inventoryDictionary` 
WHERE 
`newel_inventoryKeywordIdDictionaryId`.`dicId` = `newel_inventoryDictionary`.`dicId` 
AND ( 
    `newel_inventoryDictionary`.`word` = 'alabaster' OR `newel_inventoryDictionary`.`word` = 'chess' 
) 
GROUP BY inventoryId 
ORDER BY COUNT(`newel_inventoryKeywordIdDictionaryId`.`inventoryId`) DESC;

来源

2015-06-14 19:37:51

谢谢。我选择了Salman A的答案，因为它是在您之前提交的，但您的作品也是如此。 – kambythet

你只需要把聚合在ORDER BY。但是，您还应该：

使用明确的join语法。从不在from子句中使用逗号。
使用表别名。他们使查询更容易编写和阅读。
使用in而不是一堆or语句。

下面是该查询的改进版本：

SELECT kdi.inventoryId 
FROM newel_inventoryKeywordIdDictionaryId kdi JOIN 
    newel_inventoryDictionary id 
    ON kdi.dicId = id.dictId 
WHERE id.word IN ('alabaster', 'chess') 
GROUP BY kdi.inventoryId 
ORDER BY COUNT(*) DESC;

来源

2015-06-14 19:52:07

按列排序但在结果中不包括该列

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