如何在python中将每个新实例分配给python(numpy数组)中的新维/列的python循环?说: y=[0,1,2]
z=numpy.zero(3,3)
for i in range(3):
z[i,:]=sin(i*math.pi*2-y)
不行。我想输出数组是: 1: sin(0*math.pi*2-0) 2: sin(0*math.pi*2-1) 3: sin(0
我试图计算混淆矩阵后,我进行决策树模型 # tree model
tree <- rpart(LoanStatus_B ~.,data=train, method='class')
# confusion matrix
pdata <- predict(tree, newdata = test, type = "class")
confusionMatrix(data = pdata, r