无法将字符串与数组进行比较

Question

我尝试了不同的解决方案，无法找出为什么我无法将字符串与数组字符串进行比较。

这是我曾尝试：

function checkWin(){ 
 
    let emptyword =["h,","e,","l,","l","o"] 
 
    let computerword= "hello"; 
 
    var a = emptyword.join(""); 
 
    let b = computerword.toString(); 
 
    let c = a.toString(); 
 

 
    console.log("computerword :" + b); 
 
    console.log("emptyword is:" + c); 
 

 
    if(b === c) { 
 
    console.log("someone has won"); 
 
    } else if (b != c) { 
 
    console.log("b is not same as c");      
 
    } 
 
} 
 
checkWin()

我不能去“有人曾荣获”作为控制台打印值超出然而，当条件是不正确的两个是相同的值，即hello和hello。

任何支持是最受欢迎的。

Answer 1

这是一个错字。您的阵列是元件

• 的列表中的 “H”
• 的 “e，”
• “L”
• “L”
• “○”

的前三个元素包含逗号作为字符串的一部分。

正确的代码是：

function checkWin() { 
 
    let emptyword = ["h", "e", "l", "l", "o"] 
 
    let computerword = "hello"; 
 
    var a = emptyword.join(""); 
 
    let b = computerword; 
 

 
    console.log("computerword: " + b); 
 
    console.log("emptyword is: " + a); 
 

 
    if (a === b) { 
 
    console.log("someone has won"); 
 
    } else if (a !== b) { 
 
    console.log("b is not same as c"); 
 
    } 
 

 
} 
 

 
checkWin()

变化

let emptyword = ["h,", "e,", "l,", "l", "o"] 

到

let emptyword = ["h", "e", "l", "l", "o"] 

修复它。

Answer 2

我已经通过“Array.match（）”解决了我的问题，基本上，如果它找不到匹配项，它将在找到匹配项时返回'null'，它将显示匹配项。

这里是我解决我的这个难题

function checkWin(){ 

      var a = emptyword.join(""); 
      var b = computerword; 
      var c= b.match(a); 

      // for debug purpose only  
     console.log("match word so far...:"+ c); 

    if(c != null) 
     { 
      console.log("match win"); 
      // clear the previous information 
      document.getElementById("correctguess").innerHTML =" "; 

      document.getElementById("correctguess").innerHTML ="You have Won well done"; 

     } 
     // for debug purpose only 
     console.log("emptyword is:"+ a); 
     console.log("computerword is: "+ b); 


}// end CheckWin