SQL count语句

Question

我有一个表名作为JOB_Details和数据显示如下：

Age   Department:IT   
       Male  Female 
30yrs   5   1    
30-34yrs  3   2    
35-39yrs  4   4    
40-49yrs  2   3    
50-54yrs  1   0    

，并假设输出会喜欢：

Age   Department:IT   Total 
       Male  Female 
30yrs   5   1    6 
30-34yrs  3   2    5 
35-39yrs  4   4    8 
40-49yrs  2   3    5 
50-54yrs  1   0    1 
Total   15   10    25 

我该怎么办呢？因为当使用计数和按功能分组时，结果结果将不是我想要的。有人能介意给我一些建议吗？为了您的信息，我使用Oracle。

Answer 1

SELECT AGE, MALE, FEMALE, SUM(MALE + FEMALE) AS TOTAL 
FROM JOB_DETAILS 
GROUP BY AGE 

编辑：

如果你想运行总，你将不得不使用ROLLUP（SQL Server）的

SELECT AGE, MALE, FEMALE, SUM(MALE + FEMALE) AS TOTAL 
FROM JOB_DETAILS 
GROUP BY AGE 
WITH ROLLUP 

Answer 2

尝试使用union all这样的：

SELECT age, Male, Female, nvl(Male,0) + nvl(Female,0) as total 
FROM JOB_Details 
union all 
SELECT 'TOTAL', sum(Male), sum(Female), sum(nvl(Male,0) + nvl(Female,0)) 
FROM JOB_Details 

观看次数：

create view vJOB_Details 
SELECT (CASE WHEN age='30' THEN Count(EMPLID) 
      WHEN age='34' THEN Count(EMPLID) 
      WHEN age='39' THEN Count(EMPLID) 
      WHEN age='49' THEN Count(EMPLID) 
      WHEN age='54' THEN Count(EMPLID) 
      ELSE NULL 
     END) TOTAL_COLUMN , 
     (CASE WHEN GENDER1='M' THEN Count(EMPLID) 
       WHEN GENDER1='F' THEN Count(EMPLID) 
       ELSE NULL 
     END) TOTAL_GENDER 
FROM job_details 
GROUP BY age,GENDER 

SELECT age, Male, Female, nvl(Male,0) + nvl(Female,0) as total 
FROM vJOB_Details 
union all 
SELECT 'TOTAL', sum(Male), sum(Female), sum(nvl(Male,0) + nvl(Female,0)) 
FROM vJOB_Details;