iOS 5谷歌JSON - 如何解析嵌套的对象？

Question

我试图解析一个YouTube播放列表：

如果我的JSON的结构类似：

{"apiVersion" .... 
"items":[{"id2":"some-id","title":"songtitle", 

我完全能够通过解析标题：

// Fill array 
NSArray *items = [json objectForKey:@"items"]; 

// Get item from tableData 
NSDictionary *item = [tableData objectAtIndex:[indexPath row]]; 
// Set text on textLabel 
[[cell textLabel] setText:[item objectForKey:@"title"]]; 

但如果JSON是这样的：

{"apiVersion" .... 
"items":[{"id1": .... "video":{"id2":"some-id","title":"songtitle", 

我怎样才能达到嵌套目标ct标题？

只是一个简单的事情，但我现在敲我的头在这几个小时。感到沮丧，谢谢你的建议！

[编辑] 这是一个完整的结构：

{ 
    "items": 
    [ 
    { 
    "video": 
      { 
       "title": "Number One", 
       "description": "Description one" 
      },  
      { 
      "title": "Number two", 
       "description": "Description two" 
      }, 
      { 
       "title": "Number three", 
       "description": "Description three" 
      } 
    }, 
    { 
    "video": 
      { 
     "title": "Number One", 
      "description": "Description one" 
      }, 
      { 
       "title": "Number two", 
       "description": "Description two" 
      }, 
      { 
       "title": "Number three", 
       "description": "Description three" 
      } 
    } 

    ] 
} 

Answer 1

的问题是，你的JSON是无效的。所有的titles应该在数组中对吗？所以他们必须在[]中。您可以使用例如下面的网站“调试”你的JSON：

http://jsonformatter.curiousconcept.com/

此外，在iOS 5中，你可以使用新的内置JSON API。这里是一个很好的教程是： http://www.raywenderlich.com/5492/working-with-json-in-ios-5

尽管如此，这里是你的JSON应该什么样子我想：

{ 
    "items":[ 
     { 
     "video":[ 
      { 
       "title":"Number One", 
       "description":"Description one" 
      }, 
      { 
       "title":"Number two", 
       "description":"Description two" 
      }, 
      { 
       "title":"Number three", 
       "description":"Description three" 
      } 
     ] 
     }, 
     { 
     "video":[ 
      { 
       "title":"Number One", 
       "description":"Description one" 
      }, 
      { 
       "title":"Number two", 
       "description":"Description two" 
      }, 
      { 
       "title":"Number three", 
       "description":"Description three" 
      } 
     ] 
     } 
    ] 
} 

与您的项目好运;）

Answer 2

NSMutableArray *items = [json valueForkey:@"items"]; 
for(int i =0;i<[items count]; i++) 
{ 
    NSMutableArray *arrtitle = [[[items objectAtIndex:i]valueForkey:@"Video"]copy]; 
    for(int j =0;j<[arrtitle count]; j++) 
    { 
    NSString *title = [[arrtitle objectAtIndex:j]valueForkey:@"title"]; 
    } 
} 

也许这会帮助你。

Answer 3

试试这个：

NSArray *items = [[json valueForkey:@"items"]valueForkey:"video"];