我有以下JSON对象:解析使用JSON框架嵌套JSON对象为目标C
{
"response": {
"status": 200
},
"messages": [
{
"message": {
"user": "value"
"pass": "value",
"url": "value"
}
]
}
}
我使用JSON-框架(也尝试JSON触摸)通过该解析和创建一本字典。我想访问“消息”块,并取出“用户”,“传递”和“网址”值。
在对象 - 我有以下代码:
// Create new SBJSON parser object
SBJSON *parser = [[SBJSON alloc] init];
// Prepare URL request to download statuses from Twitter
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:myURL]];
// Perform request and get JSON back as a NSData object
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
// Get JSON as a NSString from NSData response
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];
//Print contents of json-string
NSArray *statuses = [parser objectWithString:json_string error:nil];
NSLog(@"Array Contents: %@", [statuses valueForKey:@"messages"]);
NSLog(@"Array Count: %d", [statuses count]);
NSDictionary *results = [json_string JSONValue];
NSArray *tweets = [[results objectForKey:@"messages"] objectForKey:@"message"];
for (NSDictionary *tweet in tweets)
{
NSString *url = [tweet objectForKey:@"url"];
NSLog(@"url is: %@",url);
}
我可以拉出来“消息”和看到所有的“消息”块,但我无法解析更深并拉出“用户“,”通行证“和”网址“。
的JSON字符串格式不正确,就像你在这里写的那样。消息数组有两个开放的花括号,并且只有一个关闭。 – Felixyz 2010-03-10 09:05:11