我试图解析谷歌地方api的json结果。我使用http方法调用它,我得到了字符串中的json结果 我该如何解析它?我收到文档并在互联网上观看了两个博客(一个使用谷歌api库和一个似乎已经过时),并没有帮助我如何解析谷歌的地方json
我使用的是标准的java JSONobject和Gson谷歌,但我无法找出解析它的好方法(我打电话给搜索地方法) 你有什么建议? 感谢ü
你好,对不起,忘了展现JSON响应:
{
"html_attributions" : [
"Listings by \u003ca href=\"http://www.yellowpages.ca/\"\u003eYellowPages.ca\u003c/a\u003e"
],
"results" : [
{
"geometry" : {
"location" : {
"lat" : 45.39318670,
"lng" : -75.68352930
},
"viewport" : {
"northeast" : {
"lat" : 45.40102170,
"lng" : -75.66752190
},
"southwest" : {
"lat" : 45.38535060,
"lng" : -75.69953670
}
}
},
"icon" : "http://maps.gstatic.com/mapfiles/place_api/icons/geocode-71.png",
"id" : "6a3f8ef9aae04c8a23c80ab814e8c75a8b685292",
"name" : "Old Ottawa South",
"reference" : "adsadada",
"types" : [ "neighborhood", "political" ],
"vicinity" : "Ottawa"
},
{
"geometry" : {
"location" : {
"lat" : 45.394630,
"lng" : -75.6837250
}
},
"icon" : "http://maps.gstatic.com/mapfiles/place_api/icons/movies-71.png",
"id" : "59519a28667351790456ab80aba982347546b2f6",
"name" : "Mayfair Theatre",
"rating" : 4.10,
"reference" : "dfdsf",
"types" : [ "movie_theater", "establishment" ],
"vicinity" : "1074 Bank Street, Ottawa"
}
]
}
我要抢的结果部分(并让说,结果只为简单的第一项)和我做了什么是以下内容:
JSONObject jso = new JSONObject(response);
String result = jso.getJSONArray("results").getJSONObject(0).toString();
JsonPlacesResult d = new Gson().fromJson(result, JsonPlacesResult.class);
where JsonPlacesResult is
class JsonPlacesResult{
private JsonPlaces jsonPlaces;
public JsonPlaces getJsonPlaces(){return jsonPlaces;}
}
class JsonHtml{
private String html_attribution;
}
class JsonPlaces{
private Geometry geo;
private String icon;
private String id;
private String name;
private String rating;
private String reference;
private String types;
private String vicinity;
}
class Geometry{
private JsonLocation loc;
}
class JsonLocation{
private String lat;
private String lng;
}
我结束了d中的空对象吗???为什么是这样!我做错了什么 谢谢
您可以添加收到JSON所以,我们并不需要寻找它自己呢? – 2012-03-10 09:18:02