PHP $ json的谷歌地图解析

我有以下代码：

<?php 
$q = "http://maps.googleapis.com/maps/api/distancematrix/json?origins=35.0078,-97.0929&destinations=45.2078,-97.0929&mode=driving&sensor=false"; 

$json = file_get_contents($q); 

$details = json_decode($json, TRUE); 

echo "<pre>"; print_r($details); echo "</pre>"; 
?>

结果是：

Array 
(
    [destination_addresses] => Array 
     (
      [0] => 150th St, Summit, SD 57266, USA 
     ) 

    [origin_addresses] => Array 
     (
      [0] => 38591 Patterson Rd, Wanette, OK 74878, USA 
     ) 

    [rows] => Array 
     (
      [0] => Array 
       (
        [elements] => Array 
         (
          [0] => Array 
           (
            [distance] => Array 
             (
              [text] => 1,299 km 
              [value] => 1299343 
             ) 

            [duration] => Array 
             (
              [text] => 13 hours 26 mins 
              [value] => 48361 
             ) 

            [status] => OK 
           ) 

         ) 

       ) 

     ) 

    [status] => OK 
)

我需要从$ JSON仅距离（1299公里）提取。我不知道如何做到这一点。任何帮助非常感谢。

来源

2012-04-13 Carly

看来这是一个非常类似的问题：http://stackoverflow.com/questions/2703916/parsing-data-from-google-maps-api-v3-with-json-with-php – andresf 2012-04-13 23:17:40

<?php $q = "http://maps.googleapis.com/maps/api/distancematrix/json?origins=35.0078,-97.0929&destinations=45.2078,-97.0929&mode=driving&sensor=false"; 

$json = file_get_contents($q); 
$details = json_decode($json); 
$distance=$details->rows[0]->elements[0]->distance->text; 
echo $distance; ?>

来源

2013-04-11 07:21:04

PHP $ json的谷歌地图解析

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