OVER SQL在SSRS

Question

构建物中不支持我有，我想创建在SSRS数据集的查询，但我得到一个错误的说法，

The OVER SQL construct or statement is not supported.

我使用的查询是如下：

SELECT AM, REP, PRIM_SPEC, SUM(TOT_CALL) 
FROM (
     SELECT AM, REP, SUM(TOT_CALL) as TOT_CALL, 
     CASE 
      WHEN ROW_NUMBER() OVER (PARTITION BY REP ORDER BY SUM(TOT_CALL) DESC) > 5 
      THEN 'Other' 
      ELSE prim_spec 
     END AS prim_spec 
     FROM DEMO_CALL 
     WHERE PERIOD >= @Mese 
     AND (REP IN (@REP)) 
     AND (AM = @AM) 
     GROUP BY AM, REP, prim_spec 
) A 
GROUP BY AM, REP, PRIM_SPEC 
ORDER BY 1,2,4 DESC 

我该如何使用OVER SQL Construct来解决这个问题？

Answer 1

这不是SSRS的问题，而是SQL语句本身。在生成之前，您无法比较您的ROW_NUMBER。试试这个：

SELECT distinct AM, REP, TOT_CALL, 
CASE 
    WHEN RN > 5 
    THEN 'Other' 
    ELSE prim_spec 
    END AS prim_spec 
FROM (
SELECT AM, REP, SUM(TOT_CALL) as TOT_CALL, ROW_NUMBER() OVER (PARTITION BY REP ORDER BY SUM(TOT_CALL) DESC) as RN 
FROM DEMO_CALL 
WHERE PERIOD >= @Mese 
    AND (REP IN (@REP)) 
    AND (AM = @AM) 
GROUP BY AM, REP 
) DEMO_CALL 
GROUP BY AM, REP, prim_spec 
ORDER BY 1,2,4 DESC