我需要创建4个颜色渐变逻辑。其中一个帖子给了我计算4种颜色梯度的模式。但是我有差异来实现它。4颜色渐变逻辑需要
我能计算出E点的颜色(中间的一个),但我不知道如何开发梯度从中
我的代码
COLORREF NewColor = RGB(255,0,0);
COLORREF NewColor2 = RGB(0,255,0);
COLORREF NewColor3 = RGB(0,0,255);
COLORREF NewColor4 = RGB(255,255,0);
red_low = GetRValue(NewColor);
blue_low = GetBValue(NewColor);
green_low = GetGValue(NewColor);
red_high = GetRValue(NewColor2);
green_high= GetGValue(NewColor2);
blue_high = GetBValue(NewColor2);
red_low2 = GetRValue(NewColor3);
blue_low2 = GetBValue(NewColor3); // divide the difference in colours by the number of steps
green_low2 = GetGValue(NewColor3);
red_high2 = GetRValue(NewColor4);
green_high2 = GetGValue(NewColor4); // divide the difference in colours by the number of steps
blue_high2 = GetBValue(NewColor4);
double distance_a = sqrt((double)((0-W)^2+(0-H/2)^2));
double distance_b = sqrt((double)((350-W/2)^2+(0-H/2)^2));
double distance_c = sqrt((double)((350-W/2)^2+(100-H/2)^2));
double distance_d = sqrt((double)((0-W/2)^2+(100-H/2)^2));
double sum_distances = distance_a + distance_b + distance_c + distance_d;
double red = (red_low*distance_a + red_high*distance_b + red_low2*distance_c+ red_high2*distance_d)/sum_distances;
double green = (green_low*distance_a + green_high*distance_b + green_low2*distance_c+ green_high2*distance_d)/sum_distances;
double blue = (blue_low*distance_a + blue_high*distance_b + blue_low2*distance_c+ blue_high2*distance_d)/sum_distances;
COLORREF Color_E= RGB(red,green,blue);
安逸帮助如何futher码是赞赏。
你想做什么?插入矩形的颜色? NewColori是角落里的颜色吗? – user168715 2010-06-04 19:45:12
是的,我想创建一个方形或四角有四种颜色的矩形。屏幕上的每个像素应显示这四种颜色的适当组合。我需要使用SetPixel或使用memcpy复制到frambuffer。新颜色是角落处的颜色。 – user358791 2010-06-04 19:53:00
您*需要使用''中的LinearGradientBrush来做到这一点。没有重新发明那个轮子的意义。 –
2010-06-04 20:16:40