2010-01-13 185 views
4

有没有办法在CSS中创建颜色渐变而不使用图像文件?CSS创建颜色渐变

我想给一个DIV带有颜色渐变的背景,使它看起来有光泽。

回答

7

Safari浏览器(WebKit的)支持它: http://webkit.org/blog/175/introducing-css-gradients/

的Firefox 3.6+支持它: https://developer.mozilla.org/en/CSS/-moz-linear-gradient

W3规范定义了支持它: http://dev.w3.org/csswg/css3-images/#gradients-

你也可以使用Modernizr的到检测支持并退回到图像上: http://www.modernizr.com/docs/#cssgradients

+2

嗯,WebKit继续前进,发明了自己不同于W3的语法。天才。但请记住,所谓的“定义”只不过是一个草稿,所以W3C没有定义任何内容,他们仍在思考它的样子。 – Joey 2010-01-13 06:56:35

1

Webkit浏览器支持像这样的纯CSS渐变(see this example in Safari or Chrome) - 但实际上,对于跨浏览器实现而言,您需要使用图像。

+1

虽然仍然使用图像,但灵活的解决方案:http://www.alistapart.com/articles/supereasyblendys/ – donut 2010-01-13 06:53:36

2
2

肯定的是(用颜色:皇家蓝,十六进制代码:#002366为例(例如摘自:http://www.99colors.net/name/royal-blue):

<div class="gradient">[Your DIV text and what not]</div> 

/* CSS Background Gradient */ 
.gradient 
{ 
    background-color: #628AD9; 
    /* For WebKit (Safari, Chrome, etc) */ 
    background: #628AD9 -webkit-gradient(linear, left top, left bottom, from(#001640), to(#628AD9)) no-repeat; 
    /* Mozilla,Firefox/Gecko */ 
    background: #628AD9 -moz-linear-gradient(top, #001640, #628AD9) no-repeat; 
    /* IE 5.5 - 7 */ 
    filter: progid:DXImageTransform.Microsoft.gradient(startColorstr=#001640, endColorstr=#628AD9) no-repeat; 
    /* IE 8 */ 
    -ms-filter: "progid:DXImageTransform.Microsoft.gradient(startColorstr=#001640, endColorstr=#001640)" no-repeat; 
} 
1

转至http://www.colorzilla.com/gradient-editor/#ffffff+0,e5e5e5+100;White+3D

您会看到它属在此处为显示的光泽渐变测试以下代码。您可以更改渐变并复制新代码。

background: rgb(255,255,255); /* Old browsers */ 
/* IE9 SVG, needs conditional override of 'filter' to 'none' */ 
background: url(data:image/svg+xml;base64,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); 
background: -moz-linear-gradient(top, rgba(255,255,255,1) 0%, rgba(229,229,229,1) 100%); /* FF3.6+ */ 
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(255,255,255,1)), color-stop(100%,rgba(229,229,229,1))); /* Chrome,Safari4+ */ 
background: -webkit-linear-gradient(top, rgba(255,255,255,1) 0%,rgba(229,229,229,1) 100%); /* Chrome10+,Safari5.1+ */ 
background: -o-linear-gradient(top, rgba(255,255,255,1) 0%,rgba(229,229,229,1) 100%); /* Opera 11.10+ */ 
background: -ms-linear-gradient(top, rgba(255,255,255,1) 0%,rgba(229,229,229,1) 100%); /* IE10+ */ 
background: linear-gradient(to bottom, rgba(255,255,255,1) 0%,rgba(229,229,229,1) 100%); /* W3C */ 
filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='#ffffff', endColorstr='#e5e5e5',GradientType=0); /* IE6-8 */