2017-10-18 55 views
2

因此,我已经开始使用Java创建GUI的基础知识。我已经开始创建一个基本的数学程序,该程序将解决输入通过选项窗格输入的二次方程。但是,我注意到,只要没有想象的解决方案,该计划就会给我提供解决方案。 下面是代码:使用javax.swing.JOptionPane输入时的计算错误

package window.math; 
import javax.swing.JOptionPane; 

public class WindowMath { 

public static void Solve(double a, double b, double c){ //Gives the input of A, B, C to the formula 
    double x; 
    x = Math.pow(b,2) - 4 * a * c; //Determines whether solution will have imaginary numbers or not 
    if (x >= 0){ //Real Solution output 
     double y; 
     double z; 
     double j; 
     double k; 
     double l; 
     y = -b + Math.sqrt(x); 
     z = -b - Math.sqrt(x); 
     j= 2 * a; 
     k = y/j; 
     l = z/j; 
     JOptionPane.showMessageDialog(null, "The solutions are x = " + k + " and x = " + l + ".", "Quadratic Solver", JOptionPane.PLAIN_MESSAGE); 
    } else { //Imaginary Solution Output 
     double j; 
     double v; 
     double w; 
     double y; 
     double z; 
     y = Math.abs(x); 
     w = Math.sqrt(y); 
     j = 2 * a; 
     v = w/j; 
     z = -b/j; 
     JOptionPane.showMessageDialog(null, "The solutions are x = " + z + " + " + v + "i and x = " + z + " - " + v + "i.", "Quadratic Solver", JOptionPane.PLAIN_MESSAGE); 
    } 
} 
public static void main(String[] args) { 
    String a = JOptionPane.showInputDialog("Enter a:"); 
    String b = JOptionPane.showInputDialog("Enter b:"); 
    String c = JOptionPane.showInputDialog("Enter c:"); 
    double num1 = Double.parseDouble(a); 
    double num2 = Double.parseDouble(b); 
    double num3 = Double.parseDouble(b); 
    Solve(num1,num2,num3); 
} 

}

当我运行三个数字,让同一个虚数的解决方案,那么该程序工作正常。然而,对于类似a = 1,b = 2和c = 1的情况,解应该是x = -1,x = -1。只有真正的解决方相反,输出结果给我“x = -1.0 + 1.0i,x = -1.0 - 1.0i。我目前使用NetBeans IDE 8.2(Build 201609300101)编码并使用Java更新1.8.0_144和JavaVM 25.144-b01。帮助将不胜感激

+1

@BrenoQ我不能相信我完全忽略了这一点,非常感谢你,希望我不要再犯这个错误, – CurlyCue

回答

2

在你的代码的问题是在下面的行(从main法):

double num3 = Double.parseDouble (b); 

它应该是:

double num3 = Double.parseDouble (c); 
+0

更快比我想的更多,但我完全同意:) – Sorontur