select sum statement

Question

我创建了这个select语句，我将转换为视图。我需要帮助。我需要能够在报告页面上添加= Yes和No的总数。

select 
    ps.BidPackage_ID, 
    ps.Project_ID, 
    SUM (case ps.Minority when 'Yes' then 1 else 0 end) MinorityTotal, 
    SUM (case ps.Gender when 'Female' then 1 else 0 end) FemaleTotal, 
    SUM(case ps.Cleveland_Resident when 1 then 1 else 0 end) ClevelandResidents, 
    ps.SubContractor 
from 
    PersonnelSummary ps 
group by 
    ps.BidPackage_ID, 
    ps.Project_ID, 
    ps.SubContractor 

Answer 1

你几乎有它：

... 
SUM (case ps.Minority when 'Yes' then 1 else 0 end) AS MinorityYes, 
SUM (case ps.Minority when 'No' then 1 else 0 end) AS MinorityNo, 
COUNT(*) AS Total, 
... 

随着Total我假设每一行应该被计算在内。这是你想要什么，如果：

• 中存在的列中的值只有“是”和“否” 或
• 值从“是”和“否”，也应计入不同总数。

Answer 2

你迫使我们猜你想要什么。你有一些人说他们是少数人，你想要一个说不的人数吗？或者，你是否希望统计“是”或“否”的人数，并排除那些拒绝说“或根本没有答案”的人？

select 
    ps.BidPackage_ID, 
    ps.Project_ID, 
    SUM (case ps.Minority when 'Yes' then 1 else 0 end) MinorityTotalYes, 
    SUM (case ps.Minority when 'No' then 1 else 0 end) MinorityTotalNo, 
    SUM (case ps.Minority when 'Yes' then 1 when 'No' then 1 else 0 end) 
    AS StatedMinorityTotal, 
    SUM (case ps.Gender when 'Female' then 1 else 0 end) FemaleTotal, 
    SUM(case ps.Cleveland_Resident when 1 then 1 else 0 end) ClevelandResidents, 
    ps.SubContractor 
from 
    PersonnelSummary ps 
group by 
    ps.BidPackage_ID, 
    ps.Project_ID, 
    ps.SubContractor