在Java中寻找GCD，Socket编程

我已经编写了以下两个用于查找两个数字的GCD的代码。（通过UDP服务器）在Java中寻找GCD，Socket编程

GCD_UDPClient.java

import java.io.*; 
import java.net.*; 

class GCD_UDPClient 
{ 
    public static void main(String args[]) throws Exception 
    { 
     BufferedReader InFromUser = new BufferedReader(new InputStreamReader(System.in)); 
     DatagramSocket ClientSocket = new DatagramSocket(); 
     InetAddress IPAddress = InetAddress.getByName("localhost"); 
     byte[] SendData = new byte[1024]; 
     byte[] ReceiveData = new byte[1024]; 

     System.out.print("First Number: "); 
     String input1 = InFromUser.readLine(); 
     System.out.print("Second Number: "); 
     String input2 = InFromUser.readLine(); 
     String Input = input1 + ' ' +input2; 

     SendData = Input.getBytes(); 
     DatagramPacket SendPacket = new DatagramPacket(SendData, SendData.length, IPAddress, 9836); 
     ClientSocket.send(SendPacket); 
     DatagramPacket ReceivePacket = new DatagramPacket(ReceiveData, ReceiveData.length); 
     ClientSocket.receive(ReceivePacket); 
     String ModifiedInput = new String(ReceivePacket.getData()); 
     System.out.println("GCD From Server: " +ModifiedInput); 
     ClientSocket.close(); 
    } 
}

GCD_UDPServer.java

import java.io.*; 
import java.net.*; 

@SuppressWarnings("unused") 
class GCD_UDPServer 
{ 
    @SuppressWarnings("resource") 
    public static void main(String args[]) throws Exception 
    { 
     DatagramSocket ServerSocket = new DatagramSocket(9836); 
     byte[] ReceiveData = new byte[1024]; 
     byte[] SendData = new byte[1024]; 
     while(true) 
     { 
      DatagramPacket ReceivePacket = new DatagramPacket(ReceiveData, ReceiveData.length); 
      ServerSocket.receive(ReceivePacket); 
      String input = new String(ReceivePacket.getData()); 
      InetAddress IPAddress = ReceivePacket.getAddress(); 
      int port = ReceivePacket.getPort(); 

      int ar[] = new int[2],i=0; 
      for (String Number: input.split(" ", 2)) 
      { 
       ar[i] = Integer.parseInt(Number); 
       i=i+1; 
      } 
      String Answer = Integer.toString(calculategcd(ar[0],ar[1])); 

      SendData = Answer.getBytes(); 
      DatagramPacket SendPacket = new DatagramPacket(SendData, SendData.length, IPAddress, port); 
      ServerSocket.send(SendPacket); 
     } 
    } 

    public static int calculategcd(int a, int b) 
    { 
     if(b%a == 0) 
      return a; 
     else 
      return calculategcd(b%a,a); 
    } 
}

ClientSocket.receive(ReceivePacket);似乎没有正常工作，任何线索，为什么？完整的代码只是为了清楚。由上述代码给出

输出：

First Number: 5 
Second Number: 25 
[waits indefinitely]

输出所需：

First Number: 5 
Second Number: 25 
GCD From Server: 5

来源

2014-02-09 Rajarshi Sarkar

任何错误讯息？怎么了？你期望发生什么？ –

@GuntramBlohm >>编辑上述代码给出的输出：'和'输出必需：'。 –

您是否在您的代码中检查了错误 >>> ar [i] = Integer.parseInt（Number）; –

您正在向服务器发送1024个字节，并且您将数据放入字符串“5 25”中。当你收到你分割的数据时，你将有“5”和“25”，其后是缓冲区中的其他字节。要么使用Number.trim()来丢弃这些额外的字节，要么发送一个较小的数据包（如果可能的话）。

来源

2014-02-09 14:56:13 helderdarocha

好的解释！ –

我有一个测试中，GCD_UDPServer.java有像

Exception in thread "main" java.lang.NumberFormatException: For input string: "12" 
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65) 
    at java.lang.Integer.parseInt(Integer.java:492) 
    at java.lang.Integer.parseInt(Integer.java:527) 
    at GCD_UDPServer.main(GCD_UDPServer.java:24)

和一个简单的例外改线24

ar[i] = Integer.parseInt(Number);

到

ar[i] = Integer.parseInt(Number.trim());

和它工作正常。

来源

2014-02-09 14:54:15

在Java中寻找GCD，Socket编程

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