最好的SQL代码来得到这个输出

Question

简而言之， 我有这些表。

Planning: 
    Date | Machine | Product | PlanningParts 

OKParts: 
    Date | Machine | Product | OKParts 

Scrap: 
    Date | Machine | Product | ScrapParts 

Trials: 
    Date | Machine | Product | TrialParts 

Breakdowns: 
    Date | Machine | Product | Minutes 

这些表可以有两个或更多记录为相同的[日期|机器|产品]，它们不是唯一的专栏。 获取此输出的最佳SQL代码（SQLite或SQL Server）是什么？

Output: 
    Date | Machine | Product | Planning | OKParts | ScrapParts | TrialParts | Minutes 

编辑： 在输出中，我需要每[日期，机器，产品]一行和列的其余部分必须是SUM （我不会说英语，对不起）

Eidted： 例子： （我不会把表“审判”，使之短）

Planning: 
    Date | Machine | Product | PlanningParts 
    1/6/12 | Blower | A001 | 100 
    2/6/12 | Blower | A002 | 100 
    2/6/12 | Assembly| B001 | 50 

OKParts: 
    Date | Machine | Product | OKParts 
    1/6/12 | Blower | A001  | 50 
    1/6/12 | Blower | A001  | 20 
    1/6/12 | Blower | A002  | 100 

Scrap: 
    Date | Machine | Product | ScrapParts | Reason 
    1/6/12 | Blower | A001  | 5   | Low Weight 
    1/6/12 | Blower | A001  | 3   | High Weight 
    2/6/12 | Assembly| B001  | 4   | Bad Cut 

Breakdowns 
    Date | Machine | Product | Minutes | Reason 
    1/6/12 | Blower | A001  | 100  | Manteinance 
    1/6/12 | Blower | A001  | 20   | Manteinance 
    2/6/12 | Assembly| B001  | 100  | Quality approval 


    OUTPUT: 
     Date | Machine | Product | Planning | OKParts | ScrapParts | Breakdowns 
     1/6/12 | Blower | A001  | 100  | 70  | 8   | 120 
     1/6/12 | Blower | A002  | 100  | 100  | 0   | 0 
     2/6/12 | Assembly| B001  | 50  | 0  | 4   | 100 

Answer 1

创建CTE unioning所有表成一个，然后用SUM aggrigate功能，添加了专栏ch日期，机器，产品组。像这样的位（未测试）：

WITH AllParts AS (
SELECT Date, Machine, Product, PlanningParts, NULL AS OKParts, NULL AS ScrapParts, NULL AS TrialParts, NULL AS Breakdowns 
FROM Planning 
UNION ALL 
SELECT Date, Machine, Product,NULL AS PlanningParts, OKParts, NULL AS ScrapParts, NULL AS TrialParts, NULL AS Breakdowns 
FROM OKParts 
UNION ALL 
SELECT Date, Machine, Product,NULL AS PlanningParts, NULL AS OKParts, ScrapParts, NULL AS TrialParts, NULL AS Breakdowns 
FROM Scrap 
UNION ALL 
SELECT Date, Machine, Product,NULL AS PlanningParts, NULL AS OKParts, NULL AS ScrapParts, TrialParts, NULL AS Breakdowns 
FROM Trials 
UNION ALL 
SELECT Date, Machine, Product,NULL AS PlanningParts, NULL AS OKParts, NULL AS ScrapParts, TrialParts, Breakdowns 
FROM BreakDowns 
) 
SELECT 
Date, Machine, Product, SUM(OKParts) AS OKParts, SUM(ScrapParts) AS ScrapParts, SUM(TrialParts) AS TrialParts, SUM(BreakDowns) AS Breakdowns 
FROM AllParts 
GROUP BY Date, Machine, Product 

Answer 2

我很想看看如果工会后相加作为该查询，总结第一次执行，以及：

WITH Vals AS (
    SELECT Date, Machine, Product, 'PlanningParts' Which, Sum(PlanningParts) Value FROM Planning GROUP BY Date, Machine, Product 
    UNION ALL SELECT Date, Machine, Product, 'OKParts', Sum(OKParts) FROM OKParts GROUP BY Date, Machine, Product 
    UNION ALL SELECT Date, Machine, Product, 'ScrapParts', Sum(ScrapParts) FROM Scrap GROUP BY Date, Machine, Product 
    UNION ALL SELECT Date, Machine, Product, 'TrialParts', Sum(TrialParts) FROM Trials GROUP BY Date, Machine, Product 
    UNION ALL SELECT Date, Machine, Product, 'Minutes', Sum(Minutes) FROM Breakdowns GROUP BY Date, Machine, Product 
) 
SELECT * 
FROM Vals 
PIVOT (Max(Value) FOR Which IN (PlanningParts, OKParts, ScrapParts, TrialParts, Minutes)) P; 

啊，这是痛苦的，但这就是你从给定的数据库设计中得到的结果。将这5个表重构为一张表，用视图取代这些表具有替代触发器可能是可行的。

注意：PIVOT适用于SQL Server 2005及更高版本。但是，你甚至都不需要PIVOT：

WITH Vals AS (
    SELECT Date, Machine, Product, 'PlanningParts' Which, Sum(PlanningParts) Value FROM Planning GROUP BY Date, Machine, Product 
    UNION ALL SELECT Date, Machine, Product, 'OKParts', Sum(OKParts) FROM OKParts GROUP BY Date, Machine, Product 
    UNION ALL SELECT Date, Machine, Product, 'ScrapParts', Sum(ScrapParts) FROM Scrap GROUP BY Date, Machine, Product 
    UNION ALL SELECT Date, Machine, Product, 'TrialParts', Sum(TrialParts) FROM Trials GROUP BY Date, Machine, Product 
    UNION ALL SELECT Date, Machine, Product, 'Minutes', Sum(Minutes) FROM Breakdowns GROUP BY Date, Machine, Product 
) 
SELECT 
    Date, Machine, Product, 
    Sum(CASE Which WHEN 'PlanningParts' THEN Value END) PlanningParts, 
    Sum(CASE Which WHEN 'OKParts' THEN Value END) OKParts, 
    Sum(CASE Which WHEN 'ScrapParts' THEN Value END) ScrapParts, 
    Sum(CASE Which WHEN 'TrialParts' THEN Value END) TrialParts, 
    Sum(CASE Which WHEN 'Minutes' THEN Value END) Minutes 
FROM Vals; 

交换文本Which值整数可能会产生速度的提高。

关于我对有关表中具有日期，机器，产品值的清单的表的评论/问题，此查询将提供这样的清单。这样做不会很好，但它应该给你这个想法。

WITH DistinctKeys AS (--wishing we had this as a real table 
    SELECT Date, Machine, Product FROM Planning 
    UNION SELECT Date, Machine, Product FROM OKParts 
    UNION SELECT Date, Machine, Product FROM Scrap 
    UNION SELECT Date, Machine, Product FROM Trials 
    UNION SELECT Date, Machine, Product FROM Breakdown 
) -- because then we could do this: 
SELECT 
    K.Date, K.Machine, K.Part, 
    (SELECT Sum(PlanningParts) FROM Planning X ON EXISTS (SELECT K.* INTERSECT SELECT X.Date, X.Machine, X.Product) PlanningParts 
    (SELECT Sum(OKParts) FROM OKParts X ON EXISTS (SELECT K.* INTERSECT SELECT X.Date, X.Machine, X.Product) OKParts 
    (SELECT Sum(ScrapParts) FROM Scrap X ON EXISTS (SELECT K.* INTERSECT SELECT X.Date, X.Machine, X.Product) Scrap 
    (SELECT Sum(TrialParts) FROM Trials X ON EXISTS (SELECT K.* INTERSECT SELECT X.Date, X.Machine, X.Product) TrialParts 
    (SELECT Sum(Minutes) FROM Breakdown X ON EXISTS (SELECT K.* INTERSECT SELECT X.Date, X.Machine, X.Product) Minutes 
FROM 
    DistinctKeys K; 

但坦率地说，这些连接都不会表现不如以前，我和@ jaypeagi的回答给工会。

还有一件事：不要假设性能将会是一个查询。即使是专家也会检查执行计划并收集真实的IO和CPU统计数据以确定此信息。您担心NULL会降低性能可能完全没有根据。

如果你在[日期，机器，产品]上的表上有好的索引，那么你可能会在UNION方法中获得相当好的性能。