java.lang.AssertionError：一个方法测试正常，但类似的一个不

，我有以下2种方法。我现在是DAO测试：java.lang.AssertionError：一个方法测试正常，但类似的一个不

public List<T> findAll() { 
    if (logger.isDebugEnabled()) { 
     logger.debug("findAll"); 
    } 
    return currentSession().createCriteria(getPersistentClass()).list(); 
} 

public int count() { 
    if (logger.isDebugEnabled()) { 
     logger.debug("count"); 
    } 
    return ((Number) currentSession().createCriteria(getPersistentClass()). 
      setProjection(Projections.rowCount()). 
      uniqueResult()).intValue(); 
}

测试片段：

@Test 
@Transactional(isolation = Isolation.SERIALIZABLE) 
public void testFindAll(){ 
    Assert.assertEquals(2566, this.employeeHibernateDAO.findAll().size()); 
} 

@Test 
@Transactional(isolation = Isolation.SERIALIZABLE) 
public void testCount(){ 
    Assert.assertEquals(2566, this.employeeHibernateDAO.count()); 
}

表中共有2566个条目，并且count与其计数成功返回，但是findAll没有。

错误：

java.lang.AssertionError: 
Expected :2566 
Actual :0 
    at org.junit.Assert.fail(Assert.java:91) 
    at org.junit.Assert.failNotEquals(Assert.java:645) 
    at org.junit.Assert.assertEquals(Assert.java:126) 
    at org.junit.Assert.assertEquals(Assert.java:470) 
    at org.junit.Assert.assertEquals(Assert.java:454) 
    at com.develop.test.data.dao.EmployeeDAOTest.testFindAll(EmployeeDAOTest.java:53) 
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) 
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) 
    at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44) 
    at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15) 
    at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41) 
    at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20) 
    at org.springframework.test.context.junit4.statements.RunBeforeTestMethodCallbacks.evaluate(RunBeforeTestMethodCallbacks.java:74) 
    at org.springframework.test.context.junit4.statements.RunAfterTestMethodCallbacks.evaluate(RunAfterTestMethodCallbacks.java:82) 
    at org.springframework.test.context.junit4.statements.SpringRepeat.evaluate(SpringRepeat.java:72) 
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild(SpringJUnit4ClassRunner.java:240) 
    at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:49) 
    at org.junit.runners.ParentRunner$3.run(ParentRunner.java:193) 
    at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:52) 
    at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:191) 
    at org.junit.runners.ParentRunner.access$000(ParentRunner.java:42) 
    at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:184) 
    at org.springframework.test.context.junit4.statements.RunBeforeTestClassCallbacks.evaluate(RunBeforeTestClassCallbacks.java:61) 
    at org.springframework.test.context.junit4.statements.RunAfterTestClassCallbacks.evaluate(RunAfterTestClassCallbacks.java:70) 
    at org.junit.runners.ParentRunner.run(ParentRunner.java:236) 
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run(SpringJUnit4ClassRunner.java:180) 
    at org.junit.runner.JUnitCore.run(JUnitCore.java:157) 
    at com.intellij.junit4.JUnit4IdeaTestRunner.startRunnerWithArgs(JUnit4IdeaTestRunner.java:71) 
    at com.intellij.rt.execution.junit.JUnitStarter.prepareStreamsAndStart(JUnitStarter.java:199) 
    at com.intellij.rt.execution.junit.JUnitStarter.main(JUnitStarter.java:62) 
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) 
    at com.intellij.rt.execution.application.AppMain.main(AppMain.java:120)

所以考虑到错误，它实际上是对特定方法返回0。我不明白为什么考虑伯爵是成功的。任何帮助？

编辑： SQL为count()：

09:56:15.180 [main] DEBUG org.hibernate.SQL - 
    select 
     count(*) as y0_ 
    from 
     EMPLOYEE this_ 
Hibernate: 
    select 
     count(*) as y0_ 
    from 
     EMPLOYEE this_

SQL为findAll()（employee3指的是更新，通过场）：

09:56:15.243 [main] DEBUG org.hibernate.SQL - 
    select 
     this_.EMP_ID as EMP1_5_2_, 
     this_.ISACTIVE as ISACTIVE5_2_, 
     this_.COMPANY_CODE as COMPANY12_5_2_, 
     this_.CORP_TITLE as CORP3_5_2_, 
     this_.DEPT_CODE as DEPT13_5_2_, 
     this_.E_MAIL as E4_5_2_, 
     this_.EMP_FIRST_NAME as EMP5_5_2_, 
     this_.HIRE_DATE as HIRE6_5_2_, 
     this_.JOB_CODE as JOB7_5_2_, 
     this_.JOB_TITLE_DESC as JOB8_5_2_, 
     this_.EMP_LAST_NAME as EMP9_5_2_, 
     this_.MANAGER_ID as MANAGER14_5_2_, 
     this_.MANAGER_INDC as MANAGER10_5_2_, 
     this_.EMP_MIDDLE_NAME as EMP11_5_2_, 
     preference2_.EMP_ID as EMP1_13_0_, 
     preference2_.UPDATED_BY as UPDATED4_13_0_, 
     preference2_.UPDATED_DATE as UPDATED2_13_0_, 
     preference2_.LANGUAGE as LANGUAGE13_0_, 
     employee3_.EMP_ID as EMP1_5_1_, 
     employee3_.ISACTIVE as ISACTIVE5_1_, 
     employee3_.COMPANY_CODE as COMPANY12_5_1_, 
     employee3_.CORP_TITLE as CORP3_5_1_, 
     employee3_.DEPT_CODE as DEPT13_5_1_, 
     employee3_.E_MAIL as E4_5_1_, 
     employee3_.EMP_FIRST_NAME as EMP5_5_1_, 
     employee3_.HIRE_DATE as HIRE6_5_1_, 
     employee3_.JOB_CODE as JOB7_5_1_, 
     employee3_.JOB_TITLE_DESC as JOB8_5_1_, 
     employee3_.EMP_LAST_NAME as EMP9_5_1_, 
     employee3_.MANAGER_ID as MANAGER14_5_1_, 
     employee3_.MANAGER_INDC as MANAGER10_5_1_, 
     employee3_.EMP_MIDDLE_NAME as EMP11_5_1_ 
    from 
     EMPLOYEE this_ 
    inner join 
     PREFERENCE preference2_ 
      on this_.EMP_ID=preference2_.EMP_ID 
    left outer join 
     EMPLOYEE employee3_ 
      on preference2_.UPDATED_BY=employee3_.EMP_ID 
Hibernate: 
    select 
     this_.EMP_ID as EMP1_5_2_, 
     this_.ISACTIVE as ISACTIVE5_2_, 
     this_.COMPANY_CODE as COMPANY12_5_2_, 
     this_.CORP_TITLE as CORP3_5_2_, 
     this_.DEPT_CODE as DEPT13_5_2_, 
     this_.E_MAIL as E4_5_2_, 
     this_.EMP_FIRST_NAME as EMP5_5_2_, 
     this_.HIRE_DATE as HIRE6_5_2_, 
     this_.JOB_CODE as JOB7_5_2_, 
     this_.JOB_TITLE_DESC as JOB8_5_2_, 
     this_.EMP_LAST_NAME as EMP9_5_2_, 
     this_.MANAGER_ID as MANAGER14_5_2_, 
     this_.MANAGER_INDC as MANAGER10_5_2_, 
     this_.EMP_MIDDLE_NAME as EMP11_5_2_, 
     preference2_.EMP_ID as EMP1_13_0_, 
     preference2_.UPDATED_BY as UPDATED4_13_0_, 
     preference2_.UPDATED_DATE as UPDATED2_13_0_, 
     preference2_.LANGUAGE as LANGUAGE13_0_, 
     employee3_.EMP_ID as EMP1_5_1_, 
     employee3_.ISACTIVE as ISACTIVE5_1_, 
     employee3_.COMPANY_CODE as COMPANY12_5_1_, 
     employee3_.CORP_TITLE as CORP3_5_1_, 
     employee3_.DEPT_CODE as DEPT13_5_1_, 
     employee3_.E_MAIL as E4_5_1_, 
     employee3_.EMP_FIRST_NAME as EMP5_5_1_, 
     employee3_.HIRE_DATE as HIRE6_5_1_, 
     employee3_.JOB_CODE as JOB7_5_1_, 
     employee3_.JOB_TITLE_DESC as JOB8_5_1_, 
     employee3_.EMP_LAST_NAME as EMP9_5_1_, 
     employee3_.MANAGER_ID as MANAGER14_5_1_, 
     employee3_.MANAGER_INDC as MANAGER10_5_1_, 
     employee3_.EMP_MIDDLE_NAME as EMP11_5_1_ 
    from 
     EMPLOYEE this_ 
    inner join 
     PREFERENCE preference2_ 
      on this_.EMP_ID=preference2_.EMP_ID 
    left outer join 
     EMPLOYEE employee3_ 
      on preference2_.UPDATED_BY=employee3_.EMP_ID

来源

2012-01-30 Nimchip

您是否尝试启用执行的SQL日志记录？（hibernate.show_sql） – 2012-01-30 21:09:27

@PeterLiljenberg我发布了我可以从日志中看到的一个编辑内容。 – Nimchip 2012-01-31 14:04:25

这似乎是'内部加入PREFERENCE'必须是问题。不知何故，你必须说服Hibernate每个'EMPLOYEE'至少有一个'PREFERENCE'，事实上，没有'EMPLOYEE'。（对吧？） – ruakh 2012-01-31 14:11:27

它是不可以想象的，你实际上有零行了联合查询？加入PREFERENCE是否成功？

来源

2012-01-31 14:16:38

我会检查一下，谢谢。 – Nimchip 2012-01-31 14:33:25

好吧，我似乎已经确定了几个很可能（但可能不是完全）产生这个问题的问题。我的偏好表没有填充，我宁愿忽略它，因为它应该默认设置为一个设置。另一个问题是，它当然会将自己链接到updatedBy字段上的实体员工。所以我不确定如何继续，所以暂时忽略它，或者简单地为员工表上的每个条目填充缺省值 - 这意味着首选项将有2566个条目，因为它是与雇员表一对一的。 – Nimchip 2012-01-31 14:54:28

我现在只是懒加载首选项，谢谢。我将其标记为答案。 – Nimchip 2012-01-31 14:58:51

java.lang.AssertionError：一个方法测试正常，但类似的一个不

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