如何使用查询功能在Drupal

Question

如何编写SQL查询功能在Drupal，

SELECT title FROM { node } WHERE type='%s' 

我想补充LIKE条件在

SELECT title FROM { node } WHERE type='%s' AND LIKE '%S%' 

我想我writtern错像查询formnat ，可以重写并告诉我，

Answer 1

只需使用％逃脱。

$result = db_query('SELECT title FROM {node} WHERE type = "%s" AND title LIKE "%%%s%%"', 'type', 'title'); 

while ($row = db_fetch_object($result)) { 
    // do stuff with the data 
} 

节点类型不需要转义。

Answer 2

好吧，所以你想LIKE运营商参考title列。使用此查询：

$sql = "SELECT title FROM node WHERE type='%s' AND title LIKE '%S%'"; 
$type = "type to use in query"; 
$title = "title to use in query";  
$result = db_result(db_query($sql, $type, $title)); 

这是因为LIKE操作符需要指定列名称。否则，您的数据库不知道您想要执行比较的值。见here。

Answer 3

drupal_query替换%%到％和％s到字符串值

所以你的代码会

$sql = "SELECT title FROM node WHERE type='%%%s' AND title LIKE '%%%S%%'"; 
$type = "type to use in query"; 
$title = "title to use in query";  
$result = db_result(db_query($sql, $type, $title)); 

Answer 4

这里是如何在一个动态查询（Drupal的7只）LIKE用一个例子：

$query = db_select('node', 'n') 
     ->fields('n', array('title')) 
     ->condition('type', 'my_type') 
     ->condition('title', '%' . db_like(search_string) . '%', 'LIKE'); 
    $result = $query->execute()->fetchCol(); 

db_like()用来逃脱，在LIKE模式工作作为通配符的字符。