显示弹出框右键单击JTree节点摆动

Question

我想显示弹出框在右键单击JTree节点只，而不是整个JTree组件。 当用户右键单击JTree节点时弹出框出现。如果他右击JTree中的空白区域，则不应该出现。那么为什么我只能检测到JTree节点的鼠标事件。我在网上搜索过很多次，但找不到解决方案，请帮助我。

感谢。

Answer 1

这里有一个简单的方法：

public static void main (String[] args) 
{ 
    JFrame frame = new JFrame(); 

    final JTree tree = new JTree(); 
    tree.addMouseListener (new MouseAdapter() 
    { 
     public void mousePressed (MouseEvent e) 
     { 
      if (SwingUtilities.isRightMouseButton (e)) 
      { 
       TreePath path = tree.getPathForLocation (e.getX(), e.getY()); 
       Rectangle pathBounds = tree.getUI().getPathBounds (tree, path); 
       if (pathBounds != null && pathBounds.contains (e.getX(), e.getY())) 
       { 
        JPopupMenu menu = new JPopupMenu(); 
        menu.add (new JMenuItem ("Test")); 
        menu.show (tree, pathBounds.x, pathBounds.y + pathBounds.height); 
       } 
      } 
     } 
    }); 
    frame.add (tree); 


    frame.pack(); 
    frame.setLocationRelativeTo (null); 
    frame.setVisible (true); 
} 

Answer 2

只是因为我最近偶然发现了这一点，我认为这是比现有的答案更容易一点点：

public static void main(String[] args) { 
    JFrame frame = new JFrame(); 
    final JTree tree = new JTree(); 

    JPopupMenu menu = new JPopupMenu(); 
    menu.add(new JMenuItem("Test")); 
    tree.setComponentPopupMenu(menu); 
    frame.add(tree); 

    frame.pack(); 
    frame.setLocationRelativeTo(null); 
    frame.setVisible(true); 
}