如何将行分组为具有多个值的列？

Question

如何将未知数量的行分组为单行，其中设置的列确定分组？

我想

Group1 Group2 Group3 Val1 Val2 Val3 
=============================================== 
John  Smith  25  1  0  0 
John  Smith  25  0  6  0 
John  Smith  25  0  0  8 
Chris  Green  30  0  3  0 
Chris  Green  30  5  0  0 

转移到

Group1 Group2 Group3 Val1 Val2 Val3 
=============================================== 
John  Smith  25  1  6  8 
Chris  Green  30  5  3  0 

Answer 1

declare @t table (group1 varchar(10),group2 varchar(20),group3 int,val1 int,val2 int,val3 int) 

insert into @t (group1,group2,group3,val1,val2,val3)values ('John','Smith',25,1,0,0), 
('John','Smith',25,1,6,0), 
('John','Smith',25,1,0,8), 
('Chris','Green',30,1,0,0), 
('Chris','Green',30,1,3,0), 
('Chris','Green',30,5,0,0) 

select distinct group1,group2,group3,MAX(val1),MAX(val2),MAX(val3) from @t 
group by group1,group2,group3 
ORDER BY group1 desc,group2 desc 

Answer 2

select Group1, Group2, Group3, SUM(val1), SUM(val2), SUM(val3) 
from tablename 
GROUP BY Group1, Group2, Group3 

Answer 3

您可以使用group by条款与sum聚合函数，但对于这个工作，你必须保证val列的数据类型是数字数据类型（int，decimal，smallint等） 此外，任何null值将由sum功能

select Group1, Group2, Group3, sum(val1), sum(val2), sum(val3) 
from <table_name> 
group by Group1, Group2, Group3 

Answer 4

您查询本身有你的答案被忽略。你想分组你的gropunames并在其他列上执行SUm。所有你需要做一个简单的查询，其中

select sum(Val1),sum(Val2), sum( Val3) from table 
group by Group1 , Group2, Group3  

http://www.w3schools.com/sql/sql_groupby.asp