我有一个integer
matrix
:高效施加条件的矩阵
set.seed(1)
counts.mat <- matrix(sample(50,29*10,replace=T),nrow=10,ncol=29)
colnames(counts.mat) <- c("ww.1m_1","ww.1m_2","wm.1m_1","wm.1m_2","wm.1m_3","wn.1m_1","wn.1m_2",
"A_1","A_2","B_1","B_2","C_1","C_2",
"ww.2m_1","ww.2m_2","ww.2m_3","wm.2m_1","wm.2m_2","wn.2m_1","wn.2m_2",
"ww.3m_1","ww.3m_2","ww.3m_3","wm.3m_1","wm.3m_2","wm.3m_3","wn.3m_1","wn.3m_2","wn.3m_3")
其元素表示从一组实验得到的特定的测量的计数(在此实施例3),其在data.frame
的这个list
描述的:
df.list <- list(df1 = data.frame(gt1=c("ww.1m","wm.1m","wn.1m"),kt1=c("A","B","C"),stringsAsFactors=F),
df2 = data.frame(gt2=c("ww.2m","wm.2m","wn.2m"),stringsAsFactors=F),
df3 = data.frame(gt2=c("ww.3m","wm.3m","wn.3m"),stringsAsFactors=F))
在每data.frame
在df.list
是其相应的实验的因素列和列的值是实际r水平。 counts.mat
的colnames
是这些因子水平的复制品,并且它们的名称遵循以下格式:
<factor.level>_<replicate>
。
这相当于df.list
。
例如,在gt1
是df.list$df1
与水平的因子:
"ww.1m" "wm.1m" "wn.1m"
,其相应的次重复在counts.mat
是:
"ww.1m_1","ww.1m_2","wm.1m_1","wm.1m_2","wm.1m_3","wn.1m_1","wn.1m_2"
鉴于:
min.replicates <- 1
min.counts <- 10
我想要做的是每个因子(列),在每个data.frame
在df.list
回报TRUE
或FALSE
如果至少min.replicates
以上至少有min.counts
以上的每一行中counts.mat
。
结果应该是一个matrix
其中它的列的数量等于df.list
因子水平和行数的总数等于counts.mat
行数。
这就是我认为这是一个缓慢的实现:
res.mat <- do.call(rbind,lapply(1:nrow(counts.mat),function(i){
return(do.call(cbind,lapply(1:length(df.list),function(l){
return(do.call(cbind,lapply(1:ncol(df.list[[l]]),function(j){
return(do.call(cbind,lapply(1:nrow(df.list[[l]]),function(k){
return(length(which(counts.mat[i,which(grepl(paste0(df.list[[l]][k,j],"_\\d+$"),colnames(counts.mat),perl=T))] >= min.counts)) >= min.replicates)
})))
})))
})))
}))
所以我在寻找的东西显著更快。
在你的'counts.mat'你有重复的列名称'wm.3m_1'和'wm.3m_2' - 如果倒数第二行上的那些是'2m'而不是比'3m'? –
对不起 - 固定 – dan