根据列的相似性检查所有其他列中的更改（续）

Question

select sum(case when NumFirstNames <> 1 then 1 else 0 end) as DifferentFirstNames, 
    sum(case when NumLastNames <> 1 then 1 else 0 end) as DifferentLastNames, 
    sum(case when NumSSN <> 1 then 1 else 0 end) as DifferentSSN, 
    sum(case when NumPhone <> 1 then 1 else 0 end) as DifferentPhone  
from (select EncounterId, count(*) as Num, 
count(distinct FirstName) as NumFirstNames, 
count(distinct LastName) as NumLastNames, 
count(distinct SSN) as NumSSN, 
count(distinct Phone) as NumPhone 
from table t 
group by EncounterId) e; 

我需要上面的查询来对表中另一列进行分组，名为FacilityCode，以及显示重复EncounterIDs的次数和列没有缺陷。

另外，除了计数（即第一个查询的结果背后的数据）之外，是否可以使用类似构建的查询来拉取“缺陷”结果？

见链接前面的问题： Check for changes in all other columns based on similarities one column

Answer 1

是。只要把该列中的子查询和聚集在外部查询：

select FacilityCode, 
     sum(case when NumFirstNames <> 1 then 1 else 0 end) as DifferentFirstNames, 
     sum(case when NumLastNames <> 1 then 1 else 0 end) as DifferentLastNames, 
     sum(case when NumSSN <> 1 then 1 else 0 end) as DifferentSSN, 
     sum(case when NumPhone <> 1 then 1 else 0 end) as DifferentPhone  
from (select EncounterId, FacilityCode, count(*) as Num, 
      count(distinct FirstName) as NumFirstNames, 
      count(distinct LastName) as NumLastNames, 
      count(distinct SSN) as NumSSN, 
      count(distinct Phone) as NumPhone 
     from table t 
     group by EncounterId, FacilityCode 
    ) e 
group by FacilityCode; 

我不知道你所说的“拉缺陷导致”的意思。但子查询（可能带有合适的having子句）将获得每个EncounterId的信息。