elseif(isset($_POST['submit']))
{
// Look for their user
$lookuser = mysql_query("SELECT * FROM `users` WHERE username='". mysql_escape_string($_POST['username']) ."'");
// If we find a row
if(mysql_num_rows($lookuser) > 0)
但我其他为,回声:An error has occured. <br> If you are sure you entered your username correctly, please contact an administrator.
mysql_num_rows PHP
我试图呼应$_POST['username'];
都工作地很好。我确定我的用户存在,这工作正常。
PHP的错误,我得到: Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in password.php on line 23
您在查询中没有执行任何错误检查。为什么不?如果查询失败,这也就不足为奇了。此参考问题显示如何:http://stackoverflow.com/questions/6198104/reference-what-is-a-perfect-code-sample-using-the-mysql-extension – 2012-03-19 22:16:21
也许多一点的代码会有所帮助。 – 2012-03-19 22:16:35
你是否回显了mysql_error()? $ lookuser = mysql_query(“SELECT * FROM'users' WHERE username ='”。mysql_escape_string($ _ POST ['username'])。“'”)or die(mysql_error()); – 2012-03-19 22:17:17