您的样本数据并不一致您的示例输出。该代码使用您的样本数据,试试这个:
DECLARE @YourTable table (id int, maintitle varchar(10), subtitle varchar(10), imagename varchar(10))
INSERT @YourTable VALUES (1,'ram' ,'raman' ,'abc.jpg')
INSERT @YourTable VALUES (2,'manu' ,'kiran' ,'a2.jpg')
INSERT @YourTable VALUES (2,'manoj' ,'kumar' ,'a3.jpg')
INSERT @YourTable VALUES (2,'chiru' ,'kumar' ,'a4.jpg')
INSERT @YourTable VALUES (3,'anu' ,'anitha','a4.jpg')
INSERT @YourTable VALUES (3,'anupam','aruna' ,'a4.jpg')
;WITH YourTableOrdered AS
(SELECT
*, ROW_NUMBER() OVER (PARTITION BY id ORDER BY id,imagename, maintitle,subtitle) AS RowNumber
FROM @YourTable
)
SELECT
t1.id,t1.maintitle,t1.subtitle,t1.imagename
,t2.imagename AS imagename2
,t3.imagename AS imagename3
FROM YourTableOrdered t1
LEFT OUTER JOIN YourTableOrdered t2 ON t1.id=t2.id and t2.RowNumber=2
LEFT OUTER JOIN YourTableOrdered t3 ON t1.id=t3.id and t3.RowNumber=3
WHERE t1.RowNumber=1
OUTPUT:基于OP的问题编辑提多/未知数量的每个ID文件
id maintitle subtitle imagename imagename2 imagename3
----------- ---------- ---------- ---------- ---------- ----------
1 ram raman abc.jpg NULL NULL
2 manu kiran a2.jpg a3.jpg a4.jpg
3 anu anitha a4.jpg a4.jpg NULL
(3 row(s) affected)
编辑。
你有三种选择:
1)代码的固定查询有足够LEFT JOINS
更像:
;WITH YourTableOrdered AS
(SELECT
*, ROW_NUMBER() OVER (PARTITION BY id ORDER BY id,imagename, maintitle,subtitle) AS RowNumber
FROM @YourTable
)
SELECT
t1.id,t1.maintitle,t1.subtitle,t1.imagename
,t2.imagename AS imagename2
,t3.imagename AS imagename3
,t4.imagename AS imagename4
,t5.imagename AS imagename5
,t6.imagename AS imagename6
,t7.imagename AS imagename7
,t8.imagename AS imagename8
FROM YourTableOrdered t1
LEFT OUTER JOIN YourTableOrdered t2 ON t1.id=t2.id and t2.RowNumber=2
LEFT OUTER JOIN YourTableOrdered t3 ON t1.id=t3.id and t3.RowNumber=3
LEFT OUTER JOIN YourTableOrdered t4 ON t1.id=t4.id and t4.RowNumber=4
LEFT OUTER JOIN YourTableOrdered t5 ON t1.id=t5.id and t5.RowNumber=5
LEFT OUTER JOIN YourTableOrdered t6 ON t1.id=t6.id and t6.RowNumber=6
LEFT OUTER JOIN YourTableOrdered t7 ON t1.id=t7.id and t7.RowNumber=7
LEFT OUTER JOIN YourTableOrdered t8 ON t1.id=t8.id and t8.RowNumber=8
WHERE t1.RowNumber=1
2)获得文件的最大数量每一个ID和然后构建一个包含该连接数的动态SQL语句。用它来获取文件的最大数量:
DECLARE @MaxFiles int
SELECT
@MaxFiles=MAX(CountOf)
FROM (SELECT
id,COUNT(*) AS CountOf
FROM @YourTable
GROUP BY id
) dt
3)所有的文件名组合成一个逗号分隔的列表中的一列,如:
DECLARE @YourTable table (id int, maintitle varchar(10), subtitle varchar(10), imagename varchar(10))
INSERT @YourTable VALUES (1,'ram' ,'raman' ,'abc.jpg')
INSERT @YourTable VALUES (2,'manu' ,'kiran' ,'a2.jpg')
INSERT @YourTable VALUES (2,'manoj' ,'kumar' ,'a3.jpg')
INSERT @YourTable VALUES (2,'chiru' ,'kumar' ,'a4.jpg')
INSERT @YourTable VALUES (2,'manu' ,'kumar' ,'a5.jpg')
INSERT @YourTable VALUES (2,'manoj' ,'kumar' ,'a6.jpg')
INSERT @YourTable VALUES (2,'chiru' ,'kumar' ,'a7.jpg')
INSERT @YourTable VALUES (3,'anu' ,'anitha','a4.jpg')
INSERT @YourTable VALUES (3,'anupam','aruna' ,'a4.jpg')
;WITH YourTableOrdered AS
(SELECT
*, ROW_NUMBER() OVER (PARTITION BY id ORDER BY id,imagename, maintitle,subtitle) AS RowNumber
FROM @YourTable
)
SELECT
t1.id,t1.maintitle,t1.subtitle
,STUFF(
(SELECT
', ' + t2.imagename
FROM @YourTable t2
WHERE t2.id=t1.id
ORDER BY t2.id,t2.imagename,t2.maintitle,t2.subtitle
FOR XML PATH(''), TYPE
).value('.','varchar(max)')
,1,2, ''
) AS imagenames
FROM YourTableOrdered t1
WHERE t1.RowNumber=1
ORDER BY t1.id
OUTPUT:
id maintitle subtitle imagenames
----------- ---------- ---------- -------------------------------------------------
1 ram raman abc.jpg
2 manu kiran a2.jpg, a3.jpg, a4.jpg, a5.jpg, a6.jpg, a7.jpg
3 anu anitha a4.jpg, a4.jpg
(3 row(s) affected)
您的输出与您的输入不符。你的输出中的part1来自哪里?为什么3会是* anu *而不是* anupam *。我们可以猜出这些东西,但只要提到它会更容易。 – 2010-11-24 13:33:04