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我想格式化链接列表,以便每行打印5个节点。我不确定如何做到这一点,因为我是运营商重载的新手。下面是一些我尝试,但即时通讯固守成规,并不能似乎掌握概念通过重载格式化链接列表输出<<
ostream &operator<<(ostream &os, List &s){
nodeType<Type>* current = s.head;
int i = 0;
while (current != NULL) //while more data to print
{
os << current->info << " ";
current = current->link;
++i;
if (i % 5 == 0) {
cout << '\n';
i = 0;
}
}
os << '\n'; // print the ending newline
return os;
}
其他地区代码
list.cpp
List::List()
{
node *head = NULL;
node *precurrent = NULL;
node *current = NULL;
int *temp = 0;
insert = 0;
search = 0;
remove = 0;
}
List::~List()
{
while (head != 0)
remove();
}
void List::insert(int insert)
{
if (head==null) \\If there is no list already, create a new head.
{
temp = new Node;
temp->data = insert;
head = temp;
}
else \\otherwise, insert the new node after current
{
temp = new Node;
temp->data = insert;
temp->next = current->next;
current->next = temp;
}
}
void List::search(int search)
{
current=head;
while (head->next != 0) //Cycle through the list, and if the number is found, say so
{
if (current->data = search)
cout<<"Number found."<<endl;
else
cout<<"Number not found."<<endl;
}
}
void List::remove(int remove)
{
if (head == null)
cout <<"Error. No List."<<endl;
else if (head->next == null)
{
num = head->data;
delete head;
head=null;
current=null;
}
else if (head == current)
{
temp = head->next;
num = head->data;
delete head;
head=temp;
current=temp;
}
else
{
temp = current->next;
num = current->data;
delete current;
precurrent->next = temp;
current = temp;
}
}
list.h
//CLASS PROVIDED: list
//
// CONSTRUCTOR for the list class:
// list()
// Description: Constructor will initialize variables
// Preconditions: None
// Postcondition: int insert = ""
// int search = ""
// int remove = ""
// ~list()
// Description: Destructor destroys variables
// Preconditions: None
// Postcondition: variable deleted
//
// MEMBER FUNCTIONS for the list class
//
// string insert(int)
// Description: Inserts an integer into a linked list
// Precondition: none
// Postcondition: function returns Success/Error message.
//
// string search(int);
// Description: Searches for certain linked list member and returns int to set current variable
// Precondition: none
// Postcondition: function returns int
//
// string remove(int);
// Description: removes linked list member
// Precondition: user sends int to be deleted
// Postcondition: function returned string sddress
//
// void display(void);
// Description: displays entire linked list
// Precondition: none
// Postcondition: function returns screen output
//
// void quit(void);
// Description: closes program
// Precondition: none
// Postcondition: none
//
#ifndef EMPLOYEE_H
#define EMPLOYEE_H
#include <string>
#include <iostream>
#include <cstdlib>
using namespace std;
class list
{
public:
//CONSTRUCTOR/DESTRUCTOR---------------------
list();
~list();
//GETS---------------------------------------
void insert(int);
string search(int);
string remove(int);
void display(void);
void quit(void);
private:
int insert;
int search;
int remove;
};
#endif
我编辑添加我的代码 – dtturner12 2012-02-20 04:29:15
休息@ dtturner12没有帮助,因为我不知道这有什么错我的回答你。 – 2012-02-20 04:31:01
谢谢你的回答。我现在理解推进和打印好多了。但是,我会如何将它打印到5个节点部分?我想列表打印这样的东西1 2 3 4 5“newline”6 7 8 9 10 – dtturner12 2012-02-20 04:34:50