0
高中学生试图为我们学校创建一个Facebook版本。目前我们仍然坚持在试用数据库中加入表格,然后才能发布它。为什么要删除变量?
连接表后,用户和朋友们:
users user name 1 Hallie 2 Dylan 3 Sarina 4 Dominic friends user friend 1 2 1 3 1 4 2 1 3 1 4 1 2 4 4 2 3 2 2 3 posts | user | postid | post | +------+--------+------+ | 1 | 101 | This is TigerBook! | | 2 | 102 | I am pregnant. | | 1 | 103 | I like peeps | | 4 | 104 | Giant Buzz Lightyears rock. | | 3 | 105 | Die Tucker die | | 1 | 106 | Murhur de derpity derp | | 2 | 107 | banana spaghetti squid | | 4 | 108 | chicken |
我们用这个代码:
SELECT users.user,
users.name,
posts.postid,
posts.post,
tmp.friend
FROM (SELECT friend,
user
FROM friends
GROUP BY friend) AS tmp
JOIN users
ON tmp.user = users.user
JOIN posts
ON posts.user = users.user;
而且它的结果出现:
+------+---------+--------+-------------------------+--------+ | user | name | postid | post | friend | +------+---------+--------+-------------------------+--------+ | 1 | Hallie | 101 | This is TigerBook! | 2 | | 1 | Hallie | 101 | This is TigerBook! | 3 | | 1 | Hallie | 101 | This is TigerBook! | 4 | | 2 | Dylan | 102 | I am pregnant. | 1 | | 1 | Hallie | 103 | I like peeps | 2 | | 1 | Hallie | 103 | I like peeps | 3 | | 1 | Hallie | 103 | I like peeps | 4 | | 1 | Hallie | 106 | Murhur de derpity derp | 2 | | 1 | Hallie | 106 | Murhur de derpity derp | 3 | | 1 | Hallie | 106 | Murhur de derpity derp | 4 | | 2 | Dylan | 107 | banana spaghetti squid | 1 | +------+---------+--------+-------------------------+--------+
它删除了用户3和4发布的帖子104,105和108.并且它忽略了用户2与3和4的朋友的事实。 4,以及它所显示的1。
为什么不提出用户3和4?我们应该尝试一个不同的代码?
您正在使用什么数据库?将其添加为标签。 – GrandMasterFlush 2013-04-25 15:10:47