2016-08-12 99 views
1

在下面的代码中,为什么我必须将num变量设置为global而不是folderrename_prefix?如果我从功能中删除global,则num不能用于功能,但folderrename_prefix变量仍可以?我不明白。有人能解释我对全球和地方变数的误解吗?由于为什么有些变量需要全局性而其他变量不需要?

import os 

# User Input 
folder = r'F:\Pictures\2016\iPhone Pics\rename_test' 
rename_prefix = 'Renamed_' # ENTER WHAT YOU WANT PREFIX OF IMAGE TO BE 
num = 0 

def file_renamer(): 
    global num 
    for root, dir2, files in os.walk(folder): 
     print 'Renaming Files in {} \n'.format(root) 
     if len(dir2) > 0: 
      print 'Found the following sub folders {} \n'.format(dir2) 
     #print 'Found {} subfolders named {} and {}'.format(len(dir2),dir2[0],dir2[1]) 
     #num = 0 uncomment if you want each folder to start renaming files at 0 
     for x in files: 
      local_folder = os.path.join(folder, root) 
      old = os.path.join(local_folder, x) 
      #if x.startswith('IMG'): 

      if old.lower().endswith(('.jpg')): 

       print 'Renaming {0}'.format(x) 
       num2 = '{0}.jpg'.format(num) 
       rename_name = rename_prefix + num2 
       rename_path = os.path.join(local_folder, rename_prefix + num2) 
       os.rename(old, rename_path) 
       print 'Successfully renamed {0} to {1} \n'.format(x, rename_name) 
       num += 1 
      elif old.lower().endswith('.png'): 
       print 'Renaming {0}'.format(x) 
       num2 = '{0}.png'.format(num) 
       rename_name = rename_prefix + num2 
       rename_path = os.path.join(local_folder, rename_prefix + num2) 
       os.rename(old, rename_path) 
       print 'Successfully renamed {0} to {1} \n'.format(x, rename_name) 
       num += 1 

      elif old.lower().endswith('.mov'): 
       print 'Renaming {0}'.format(x) 
       num2 = '{0}.mov'.format(num) 
       rename_name = rename_prefix + num2 
       rename_path = os.path.join(local_folder, rename_prefix + num2) 
       os.rename(old, rename_path) 
       print 'Successfully renamed {0} to {1} \n'.format(x, rename_name) 
       num += 1 

      else: 
       print 'IDK what file type {0} is !!, skipping...'.format(x) 
       continue 
      #else: 
       #print '{} Does not meet renaming criteria, moving to next file'.format(x) 
       #continue 

    print 'Finished Renaming all files in {}'.format(folder) 


file_renamer()enter code here 
+1

因为您永远不会更改'folder'或'rename_prefix'的值。 –

+3

你不修改'''''''''','''''''''''''''''''''',所以你不需要'''全球'''。但是你在函数内更新'''num''',所以你需要使用'''global'''。 –

回答

1
x = 0 

def function_name(): 
    x = 2 


function_name() 

x #yields:0 

,但如果你定义:

def function_name(): 
    global x 
    x = 2 

然后执行

function_name() 
x #yields 2 
2

随着人们在评论中指出的,你不需要使用的原因globalfolderrename_prefix,但你做为num是th在你设置后者的时候,你只是在阅读前两篇文章。

如果你没有申报num全球性的,会发生什么样的是,分配到num将创建并分配到一个新的局部变量num这将影着全球num,而不是实际设置已定义的全局值正如你所期望的那样。