使用unix时间戳在一个月内SQL计数记录

Question

我试图返回每个月内的记录数并按月/年分组结果。

模式看起来是这样的：

id title timestamp 

我一直在寻找周围，但我期待它，我不能得到的结果。谢谢。

Answer 1

格式化时间戳，然后按它进行分组。

组的月份：

SELECT DATE_FORMAT(t.timestamp, "%Y-%m") AS "_Month", COUNT(*) 
FROM yourtable as t 
GROUP BY _Month; 

组的年份：

SELECT DATE_FORMAT(t.timestamp, "%Y") AS "_Year", COUNT(*) 
FROM yourtable as t 
GROUP BY _Year; 

如果时间戳字段存储为unixtime价值，只是包装FROM_UNIXTIME()绕场：

SELECT DATE_FORMAT(FROM_UNIXTIME(t.timestamp), "%Y") AS "_Year", COUNT(*) 
FROM yourtable as t 
GROUP BY _Year; 

Answer 2

SELECT YEAR(`timestamp`) AS Y, MONTH(`timestamp`) AS M, COUNT(1) AS C 
FROM that_table 
GROUP BY YEAR(`timestamp`), MONTH(`timestamp`) 
ORDER BY YEAR(`timestamp`), MONTH(`timestamp`)