如何从每个组找到最大值，并显示其信息使用“分组依据”

Question

例如，我创建一个表约人contribue 2个活动

+-------------------------------------+ 
| ID Name Campaign Amount (USD) | 
+-------------------------------------+ 
| 1  A   1    10 | 
| 2  B   1    5 | 
| 3  C   2    7 | 
| 4  D   2    9 | 
+-------------------------------------+ 

任务时：对于每个广告系列，找到此人谁最有助于

预期结果（姓名，ID）是

+-----------------------------------------+ 
|  Campaign   Name   ID | 
+-----------------------------------------+ 
|  1     A    1 | 
|  2     D    4 | 
+-----------------------------------------+ 

我用“组的运动”，但结果有2列“Campagin”和“最大值”当我需要“名称“和”ID“

感谢您的帮助。 编辑：我修正了一些值，真的很抱歉

Answer 1

您可以使用分析功能是：

select name, id, amount 
from (select t.*, max(amount) over (partition by campaign) as max_amount 
     from t 
    ) t 
where amount = max_amount; 

Answer 2

尝试下一个查询： -

SELECT Campaign , Name , ID 
FROM (
     SELECT Campaign , Name , ID , MAX (Amount) 
     FROM MyTable 
     GROUP BY Campaign , Name , ID 
) temp; 

Answer 3

您还可以通过给做rank/row_number partiton by campaign，并按照amount的降序排列。

查询

;with cte as(
    select [num] = dense_rank() over(
     partition by [Campaign] 
     order by [Amount] desc 
    ), * 
    from [your_table_name] 
) 
select [Campaign], [Name], [ID] 
from cte 
where [num] = 1; 

Answer 4

只需使用Where条款与量group by运动的max： -

正如下面的通用代码： -

select a, b , c 
from tablename 
where d in 
(
    select max(d) 
    from tablename 
    group by a 
) 

演示： -

Create table #MyTable (ID int , Name char(1), Campaign int , Amount int) 
go 

insert into #MyTable values (1,'A',1,10) 
insert into #MyTable values (2,'B',1,5) 
insert into #MyTable values (3,'C',2,7) 
insert into #MyTable values (4,'D',2,9) 
go 

select Campaign, Name , ID 
from #MyTable 
where Amount in 
(
    select max(Amount) 
    from #MyTable 
    group by Campaign 
) 

drop table #MyTable 

结果： -

Answer 5

请找到相同

SELECT * 
FROM #MyTable T 
OUTER APPLY (
    SELECT COUNT(1) record 
    FROM #MyTable T1 
    where t.Campaign = t1.Campaign 
    and t.amount < t1.amount 
)E 
where E.record = 0 

输入表