我有如下3个属性的MyItem类从对象列表中选择:LINQ:分组依据,并根据最大值
class MyItem
{
private string _name;
private int _value
private DateTime _TimeStamp;
public MyItem(string name, int value, string timeStamp)
{
this._name = name;
this._value = value;
this._timeStamp = DateTime.Parse(timeStamp);
}
public string Name
{ get {return this_name; } }
public int Value
{ get {return this._value; } }
public DateTime TimeStamp
{ get {return this._timeStamp; } }
// ...
}
我也有如下MyItem列表:
var myItems = new List<MyItem>() {
new MyItem("A", 123, "23/02/2012"),
new MyItem("A", 323, "22/02/2012"),
new MyItem("B", 432, "23/02/2012"),
new MyItem("B", 356, "22/02/2012"),
// ...
}
我怎么能GROUP BY myList,以便我只剩下具有最大时间戳的项目?即结果如下:
"A" 123 23/02/2012<br>
"B" 432 23/02/2012<br>
在此先感谢。
我冒昧地编辑你的代码,我希望我没有搞砸你的例子 – BlackBear 2012-02-29 20:38:33